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Irina-Kira [14]
3 years ago
9

WORTH 100 POINTS PLEASE HURRY!!!!!!!!

Chemistry
2 answers:
neonofarm [45]3 years ago
5 0

Answer:

The answer is B

Explanation:

Less air means less air pressure. At a certain point, there is very little air pressure to push against the outward pressure of the helium inside the balloon. It will then expand until the rubber breaks, and the balloon bursts

Anastasy [175]3 years ago
4 0
The answer is actual b
Explanation
It is what is isssssss
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What may be expected when K > 1.0?
lora16 [44]

The two correct statements are:

1. The concentration of one or more of the products is small

2. The reaction will proceed to the right and favor the formation of products.

LeChatelier's Principle states that when a stress is imposed on a system at equilibrium, the equilibrium will shift to counteract the change. A reduction in the number of products cause the system to respond by making more product, which leads to K>1 and products being more favorable.

4 0
3 years ago
Read 2 more answers
3. ¿Cuál de las siguientes operaciones es correcta para calcular el número de moles de hidrógeno necesarios para producir 6 mole
Aloiza [94]

Answer:

the answer is d that is 6×2/3

4 0
3 years ago
A tank contains 200 gallons of water in which 300 grams of salt is dissolved. A brine solution containing 0.4 kilograms of salt
Nadusha1986 [10]

Answer:

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

Explanation:

given amount of salt at time t is A(t)

initial amount of salt =300 gm =0.3kg

=>A(0)=0.3

rate of salt inflow =5*0.4= 2 kg/min

rate of salt out flow =5*A/(200)=A/40

rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow

dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt

integrating factor

=e^{\int\limits (1/40) \, dt}

integrating factor =e^{(1/40)t}

multiply on both sides by  =e^{(1/40)t}

dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t

integrate on both sides

\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})

b)

after long period of time means t - > ∞

{t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>
6 0
3 years ago
Harim placed 5mL of ethanol into a container that weighs 1 gram using a dropper. He already knew the density of ethanol is 0.78
Aleks04 [339]

Answer:

there it is fella tried on ma own consciousness

8 0
3 years ago
what actually is left over of water once it self ionizes? Like what exactly are the hydrogen and hydroxide ions? Do they remain
GrogVix [38]
The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)

The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of.  These ions do stay in solution.  However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
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