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andreev551 [17]

4 years ago

8

Before the introduction of chlorofluorocarbons, sulfur dioxide (entha;py of vapourization, 6.00 kcal/mol) was used in household

refrigrators. What mass of SO2 must be evoparated o remove as much heat as evaporation of 1.00 kg of CCl2F2(enthalpy of vapourization is 17.4 kJ/mol)?
The vapourition reactions for SO2 and CCl2F2 re SO2 (i) ? SO2 and CCl2F(i) ? CCl2F2(g), respectively

1 answer:

blondinia [14]4 years ago

5 0

Answer: 367 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Enthalpy of vaporization is the amount of heat released when 1 mole of substance is converted from liquid to gaseous state.

Given : Enthalpy of vapourization of $CCl_2F_2$ = 17.4 kJ/mol

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of}CCl_2F_2=\frac{1000g}{121g/mol}=8.3moles$

1 mole of $CCl_2F_2$ produces heat = 17.4 kJ

8.3 moles of $CCl_2F_2$ produces heat = $\frac{17.4}{1}\times 8.3=144 kJ$

Given : Enthalpy of vapourization of $SO_2$ = 6.0 kcal/mol = $6\times 4.184=25.104kJ$ (1kcal=4.184kJ)

25.104 kJ heat is produced by = 1 mole of $SO_2$

144 kJ heat is produced by = $\frac{1}{25.104}\times 144=5.73mole$ of $SO_2$

Mass of $SO_2=moles\times {\text {molar mass}}=5.73\times 64=367g$

Thus 367 grams of $SO_2$ must be evoparated o remove as much heat as evaporation of 1.00 kg of $CCl_2F_2$

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solniwko [45]

The energy required to heat 40g of water from -7 c to 108 c is
1541000 joules

calculation

Q(heat)= M( mass) x c(specific heat capacity) xdelta t( change in temperature)

M= 40g= 40/1000= 0.04 Kg
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delta T ( 108 --7= 115 c)

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3 years ago

IF 500 mL of air contains 2.50x10^22 particles (atoms and molecules). how much particles do you inhale in one day if you breath

vaieri [72.5K]

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3 years ago

When balancing a chemical equation, what are the large numbers that we adjust?

Nata [24]

Answer:

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What three (3) factors determine the reactivity of elements? Explain and give examples of each.

Degger [83]

Explanation:

The three factors which determine the reactivity of elements are as follows.

(1) Number of valence electrons.

(2) Size of an atom.

(3) Electro negativity of an atom.

All these factors are explained as follows.

(1) Number of valence electrons

According to the octet rule, every atom requires to attain stability. Therefore, number of electrons in the outermost shell will decide the reactivity of an atom as every atom needs to fill its shells or sub shells as per the octet rule. As a result, the reactivity increases.

For example, the atomic number of chlorine is 17 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}$

In the 3p sub shell, there is deficiency of one electron. So, in order to attain stability chlorine atom will react readily with another species or atom which can either donate or share one electron.

Whereas an atom with completely fill shell will have low reactivity.

(2) Size of an atom

On moving down the group size of atom increases. As a result, the attraction between the nucleus and electrons decreases due to the shielding effect. Thus, the larger is an atom, the more easily it can give electrons. Therefore, the reactivity increases.

For example, the atomic number of calcium is 20 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}$

Also it is known that first shell of every atom can have 2 electrons, second shell can have 8 electrons, third shell can have 18 electrons and so on.

Since, calcium is larger in size as compared to beryllium and magnesium so it will readily loose 2 electrons to attain stability. Thus, it will attain a $Ca^{2+}$ charge.

(3) Electro negativity of an atom

An atom with uneven distribution of electrons will acquire a certain amount of charge. Thus, it becomes polar in nature and in order to gain stability, the atom will either loose or gain electrons according to its charge.

For example, atomic number of fluorine is 9 and its electronic configuration is $1s^{2}2s^{2}2p^{5}$ .

So, in order to gain stability fluorine will readily accept 1 electron to completely fill its 2p sub shell. As a result, the electronic configuration will become $1s^{2}2s^{2}2p^{6}$

Therefore, fluorine will have a charge of -1 because it has gained one electron.

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