3 years ago

Which expression correctly shows 2x^5y−2x^2y factored completely over the integers?

Mathematics

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

Option D, 2x^2y(x - 1)(x^2 + x + 1)

Step-by-step explanation:

Step 1: Factor

2x^5y - 2x^2y

2x^2y(x^3 - 1)

2x^2y(x - 1)(x^2 + x + 1)

Answer: Option D, 2x^2y(x - 1)(x^2 + x + 1)

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