Which expression correctly shows 2x^5y−2x^2y factored completely over the integers?
1 answer:
Answer:
Option D, 2x^2y(x - 1)(x^2 + x + 1)
Step-by-step explanation:
<u>Step 1: Factor</u>
2x^5y - 2x^2y
2x^2y(x^3 - 1)
<em>2x^2y(x - 1)(x^2 + x + 1)</em>
<em />
Answer: Option D, 2x^2y(x - 1)(x^2 + x + 1)
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