Question

Which expression correctly shows 2x^5y−2x^2y factored completely over the integers?

Answer 1

Answer:

Option D, 2x^2y(x - 1)(x^2 + x + 1)

Step-by-step explanation:

Step 1:  Factor

2x^5y - 2x^2y

2x^2y(x^3 - 1)

2x^2y(x - 1)(x^2 + x + 1)

Answer:  Option D, 2x^2y(x - 1)(x^2 + x + 1)