Answer:
Step-by-step explanation:
(8 - 4)/(6 - 2) = 4/4 = 1
y - 4 = x - 2
y = x + 2
The correct answer is: [C]: " x² = √32 " .
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Explanation:
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Note: Working backward, "(± 4√2)" , squared, equals what value(s)?
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Note: We are actually given 2 (TWO) solutions:
" +4√2" and "–4√2" ;
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√32 = √8 √4 = √4 √2 √4 = 4√2 ;
- √32 = -1 * √32 = - 4√2
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or:
√32 = √16 √2 = 4√2 ;
-1 * √32 = - 4√2
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However, BOTH these values, when "squared" (i.e. raised to the exponential power of "two"; will result in the same value— which is: "32" ;
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is equal to: "(4√2)² = (4)² *(√2)² = (4*4) (√2*√2) = 16*2 = " 32 " .
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√32 = √8 √4 = √4 √2 √4 = 4√2 ;
- √32 = -1 * √32 = - 4√2
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or:
√32 = √16 √2 = 4√2 ;
-1 * √32 = - 4√2
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" (4√2)² = (4)² * (√2)² = (4 * 4) (√2*√2) = 16 * 2 = " 32 " .
" (-4√2)² = (-4)² * (√2)² = (-4 *-4) (2) = 16 * 2 = " 32 " .
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The correct answer is: " 32 <span>" ; which is: Answer choice: [D]: " x</span>² = 32 " .<span>
We know that the answer is: " </span>" {" <span>± 8 "}; since we are dealing with equations that contain "x SQUARED"; that is, " x</span>²"; and when we solve for the 'square root of all values of a [variable raised to an even positive integer] ;
we take the "plus or minus" square root values ; since the value, "x" could be plus or minus; since a "negative value" multiplied by a "negative value" is a "positive value" ;
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So, the correct answer is: Answer choice: [B]: " x² = <span>± 8 " .
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Let us check our answer:
</span>√32 = √16*√2 = 4√2 ;
– √32 = – 4√2 ;
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Also, note:
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x² = 32 ; Solve for "x" ;
→ Take the square root of "each side" of the equation ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ √(x²) = √32 ;
→ | x | = √32 ;
→ x = ± √32 . Yes!
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Answer:
1)x=11
2)x=9
Step-by-step explanation:
In the picture
Answer:
g = 23/16
Step-by-step explanation:
3/16 = (-5/4) + g
Add 5/4 on both sides.
3/16 + 5/4 = g
Make denominators equal and add.
3/16 + 20/16 = g
23/16 = g
Answer:
The table that represents the nonlinear function is the one where the x-values are -7, -5 and 0 and the y-values are -3, 0 and 3.
Step-by-step explanation:
In order for a table to represent a linear function, there needs to be a consistent change in y-values divided by the change in x-values. For example, for any two points on the table when we subtract two y-values and divide by the number we get when we subtract two x-values, this change should be represented throughout the table. So, in the case of the other three tables, when we choose two points from the table, such as (-5, 7) and (-2,6) and put them into an equation (y2-y1/x2-x1) or (6-7)/(-2-(-5)) we would get a change of -1/3. However, when we apply this concept to the table where x-values are -7,-5, and 0, we see that the change is not consistent between points, so the function must be nonlinear.
