8, 8, 8, 8, 8, 9, 9, 9, 9 would work as a sequence.
Median: 8
Mean: 8.4444....
The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10
There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.
If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).
I think holding steady I’m not sure!
Step-by-step explanation:
Close. You correctly set up the integrals. When integrating e²ˣ:
∫ e²ˣ dx
½ ∫ 2 e²ˣ dx
½ e²ˣ + C
So the coefficient should be ½, not 2.
[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹
[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]
1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1
-e⁻¹ + ½ e⁻² + ½ e² − e + 1
Answer:
$618.95 rounded up. 0.004c
£388.09 on rent and $230.84 food
We can round up and state $619 to nearest tenth.
Or leave as non rounded Total $618.93
Step-by-step explanation:
27% of 1,437.40=388.09
1,437.40 - 388.09 = 1049.31
22% of 1049.31 = 230.8482
$230,84 Shown here, as not round up or down as 230.84 as £388.09 was not rounded up from 388.098.
= $618.95 rounded up. 0.004c
