All categories

2 years ago

Calculate the mass of a truck traveling at 30.56 m/s that has a starting momentum of 77,000 kg*m/s

Physics

1 answer:

Airida [17]2 years ago

4 0

Answer:

2519.63 kg

Explanation:

mass(m)=momentum (p)/velocity

=77000/30.56

=2519.63kg

You might be interested in

Which best explains satellites? The moon is a satellite of the Earth, and the Earth is a satellite of the Sun. Mercury and Pluto

expeople1 [14]

A satellite is a body that revolves around another larger body. Where the larger body has a stronger gravitational pull on the smaller body, keeping it in orbit. Thus the moon is the satellite of the Earth is a good example of this.

4 0

3 years ago

A bird flies 3.6 km due west and then 1.8 km due north. Another bird flies 1.8 km due west and 3.6 km due north. What is the ang

kondor19780726 [428]

Define unit vectors as follows:
$\hat{i}$ is in the eastern direction.
$\hat{j}$ is in the northern direction.

The position of the first bird is
$\vec{a} = -3.6 \, \hat{i} + 1.8 \, \hat{j}$

The position of the second bird is
$\vec{b} = - 1.8 \, \hat{i} + 3.6 \, \hat{j}$

Let θ = the angle between the net displacement vector for the two birds.
By definition,
$\vec{a} . \vec{b} = |a| |b| cos\theta \\\\ \theta = cos^{-1} ( \frac{\vec{a}.\vec{b}}{|a||b|} )$

$\vec{a}.\vec{b} = (-3.6)(-1.8)+(3.6)(1.8) = 12.96$
$|a| = \sqrt{3.24+12.96} =4.025$
Similarly,
|b| = 4.025

Therefore
$\theta = cos^{-1} \frac{12.96}{4.025^{2}} =36.9^{o}$

Answer: 36.9°

5 0

3 years ago

Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. The electric field at a po

gregori [183]

Answer:

E = 0 r <R₁

Explanation:

If we use Gauss's law

Ф = ∫ E. dA = $q_{int}$ / ε₀

in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.

Consequently by Gauss's law the electric field is ZERO

E = 0 r <R₁

6 0

2 years ago

Use the values provided to calculate the initial voltage

EleoNora [17]

Answer: V1= 360 V

Explanation:

7 0

2 years ago

Read 2 more answers

You can increase the capacitance of a capacitor by A. Decreasing the plate spacing B. Increasing the plate spacing. ° C. Decreas

eimsori [14]

You can increase the capacitance of a capacitor by decreasing the plate spacing (A) or by increasing the area of the plates (D).

'A' and 'D' both do the job, so the correct choice is<em> (E)</em> .

4 0

2 years ago