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umka2103 [35]
3 years ago
5

Please help I’ll give brainliest

Physics
1 answer:
lara [203]3 years ago
6 0
I think the answer is B
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An earthworm moves by using two different sets of muscles. 2. FISHES :- Fish swim by flexing their bodies and tail back and forth. Fish stretch or expand their muscles on one side of their body, while relaxing the muscles on the other side.

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3 years ago
Resistance of a conductor is directly proportional to length.<br> a. True<br> b. False
PtichkaEL [24]

If everything else is held constant ... the substance from which
the conductor is formed, its cross-sectional area, its temperature
everywhere along its length ... then yes, its resistance will be
directly proportional to its length.

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4 years ago
I have to write something here, so like hello and please help​
ExtremeBDS [4]

Answer:

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Explanation:

5 0
3 years ago
In a diffraction grating experiment, light of 600 nm wavelength produces a first-order maximum 0.350 mm from the central maximum
NARA [144]

Answer:

497.143 nm.

Explanation:

Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.

The solution to the question is through the use of the formula in the equation (1) below;

Sin θ = m × λ. ---------------------------------(1).

Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).

Also, m × λ = dc/ B -------------------------------------------(2).

We are to find the second wavelength, therefore;

λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).

Where c1 and c2 are the order maximum and m = order numbers. Hence;

λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.

7 0
3 years ago
Read 2 more answers
A particle executes simple harmonic motion with an amplitude of 3.00 cm. At what position does its speed equal half of is maximu
Mrac [35]

Answer:

x=±0.026m

Explanation:

In simple harmonic motion the maximum value of the magnitude of velocity

v_{max}=wA=\sqrt{\frac{k}{m} }A

The speed as a function of position for simple harmonic oscillator is given by

v=w\sqrt{A^{2}-x^{2}

where A is amplitude of motion

Given data

Amplitude A=3 cm =0.03 m

v=(1/2)Vmax

To find

We have asked to find position x does its speed equal half of is maximum speed

Solution

The speed of the particle the maximum speed as:

v=\frac{V_{max} }{2}\\ w\sqrt{A^{2}-x^{2}  }=\frac{wA}{2}\\  A^{2}-x^{2}=\frac{A^{2} }{4}\\ x^{2}=A^{2}- \frac{A^{2} }{4}\\ x^{2}=\frac{3A^{2}}{4} \\x=\sqrt{\frac{3A^{2}}{4}}

x=±(√3(0.03)/2)

x=±0.026m

5 0
4 years ago
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