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When monochromatic light illuminates a grating with 7000 lines per centimeter, its second order maximum is at 62.4°. what is the

zhannawk [14.2K]

When red light illuminates a grating with 7000 lines per centimeter, its second maximum is at 62.4°. What is the wavelength of this light?

ans: 633nm

6 0

3 years ago

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A charge of 1.5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How m

belka [17]

Answer:

Energy stored in the capacitor is $U=2.7\times 10^{-5}\ J$

Explanation:

It is given that,

Charge, $q=1.5\ \mu C=1.5\times 10^{-6}\ C$

Potential difference, V = 36 V

We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

$U=\dfrac{1}{2}q\times V$

$U=\dfrac{1}{2}\times 1.5\times 10^{-6}\times 36$

U = 0.000027 J

$U=2.7\times 10^{-5}\ J$

So, the potential energy is stored in the capacitor is $U=2.7\times 10^{-5}\ J$ . Hence, this is the required solution.

4 0

3 years ago

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The coordinates of a bird flying in the xy plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2

mr_godi [17]

We've seen this introduction to a question posted several times before here on Brainly, but it always stops right there. What is the question ? ? ?

8 0

3 years ago

Determine the capacitive reactance for a 20 uF capacitor that is across a 20 volt, 60 Hz source

aleksandr82 [10.1K]

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, $C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F$

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

$X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}$

$X_C=132.6\ \Omega$

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.

4 0

3 years ago

A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take

defon

Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. As is implied by the equation for power, a unit of power is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t

We calculate as follows:

500 W = 15000 J / t
t = 30 s

3 0

3 years ago