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kogti [31]
3 years ago
13

If an alveolus with an initial volume of 3 ml of air with a total pressure of 810 mmhg decreases in volume to 1.7 ml, what would

the new pressure be and in which direction would air flow? assume you are at sea level.

Physics
2 answers:
Yakvenalex [24]3 years ago
8 0
<span>This question is answered by using Boyle's law which states that P1V1=P2V2. Therefore 3ml x 810mmHg = 1.7ml * P2. P2 in this case is 1429mmHg. Air flow would be out of the body into the environment, where atmospheric pressure is approximately 760 mmHg. Higher pressure flows into lower pressure areas.</span>
devlian [24]3 years ago
3 0

The new pressure would be about 1430 mmHg.

Air would flow out of the alveolus.

\texttt{ }

<h3>Further explanation</h3>

The Ideal Gas Law and Work formula that needs to be recalled is:

\boxed {PV = nRT}

\boxed { W = P \Delta V }

<em>where:</em>

<em>W = Work ( J )</em>

<em>P = Pressure ( Pa )</em>

<em>V = Volume ( m³ )</em>

<em>n = number of moles ( moles )</em>

<em>R = Gas Constant ( 8.314 J/mol K )</em>

<em>T = Absolute Temperature ( K )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

initial volume = V₁ = 3 ml

initial pressure = P₁ = 810 mmHg

final volume = V₂ = 1.7 ml

<u>Asked:</u>

final pressure = P₂ = ?

<u>Solution:</u>

<em>We will use </em><em>Boyle's Law</em><em> to solve this problem as follows:</em>

P_1V_1 = P_2V_2

810 \times 3 = P_2 \times 1.7

P_2 = 2430 \div 1.7

P_2 \approx 1430 \texttt{ mmHg}

\texttt{ }

At sea level , the atmospheric pressure (Po) is about 760 mmHg.

Because P₂ > Po , air would flow out of the alveolus.

\texttt{ }

<h3>Learn more</h3>
  • Minimum Coefficient of Static Friction : brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

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