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svp [43]
3 years ago
11

Haley wrote the expression 24m – 6n. Kensi wrote an expression equivalent to Haley’s. Which expression could Kensi have written?

2(6m – 4n) 4(6m – 6n) 6(4m – n) 12(2m – 2n)
Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0

Answer:

C) 6(4m-n)

Step-by-step explanation:

Because 6(4m-n)=24m-6n.

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What is (+12) – (-8)?
Sergio [31]

Answer:

+12+8=+20

Step-by-step explanation:

Hope it helps you!

3 0
3 years ago
Read 2 more answers
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul
sesenic [268]

The expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,


C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}


now put the value in the formula.

5 = \sqrt{(x-6^2)+(y - 5)^2}

Thus, expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.


Learn more about equation here:

brainly.com/question/10413253

#SPJ1



4 0
1 year ago
Add the polynomials <br><br><br> (-12x^5-7x^3+12x^2+11)+(4x^3+6x^2-6x+3)
tatuchka [14]

Answer:

-12x^5-3x^3+18x^2+14

6 0
3 years ago
Solve for the roots in simplest form using the quadratic formula: x^2+14x=-45
Natalija [7]

Answer:

x = − 5 − 9

Step-by-step explanation:

Solve the equation for  x  by finding  a ,  b , and  c  of the quadratic then applying the quadratic formula. x = − 5 − 9

6 0
2 years ago
Cost of a New Car From 1970 to 1990, the average cost of a new car, C
Lunna [17]

Answer:

In year 1986 the average  cost of car is  $12,000

Step-by-step explanation:

Cost function:

C = 30.5t² + 4192

Cost = $12,000

Find:

Year

Computation:

C = 30.5t² + 4192

12,000 = 30.5t² + 4192

t = 16 year

So,

Year 1970 + 16 year

1986

So, In year 1986 the average  cost of car is  $12,000

3 0
3 years ago
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