I dont have time to do all of these right now my apolgies but Ill explain how to do it.
The 3 angles of a triangle add up to 180.
So let me show you how to do 1.
.
.
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1. 58 degrees
92, 30, ?
If we add together the first two angles,
92+30= 122
Knowing the total addition of all three angles would ne 180, we can subtract 122 from it to get the third angle.
180-122= 58
So we now know the last angle is 58 degrees because
92+30+58=180
Answer:
Hope this helped.
A brainliest is always appreciated.
Answer:
40π in^2
Step-by-step explanation:
360°/72°=5
so, each of the two shaded regions are 1/5 of the circle.
the formula for finding the area of a circle is πr^2, so:
area for one of the shaded regions:
1/5πr^2
1/5π(10)^2
1/5π100
20π in^2
this means that the area for one of the shaded regions is 20π. however, since there are two of them:
2(20π)=40π
so, the area of the shaded regions is 40πin^2
You have to divide 38.14 by 4 and your answer equals 9.535 whichirounds to 9.54
Answer:
option (a) It will be closer to 30 than to 20
Step-by-step explanation:
Data provided in the question:
For sample 1:
n₁ = 10
variance, s₁² = 20
For sample 2:
n₂ = 15
variance, s₂² = 30
Now,
The pooled variance is calculated using the formula,
![S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}](https://tex.z-dn.net/?f=S%5E%7B2%7D_%7Bp%7D%20%3D%20%5Cfrac%7B%28n_%7B1%7D-1%29%5Ctimes%20s%5E%7B2%7D_%7B1%7D%20%2B%28n_%7B2%7D-1%29%5Ctimes%20s%5E%7B2%7D_%7B2%7D%7D%7Bn_%7B1%7D%2Bn_%7B2%7D-2%7D)
on substituting the given respective values, we get
![S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}](https://tex.z-dn.net/?f=S%5E%7B2%7D_%7Bp%7D%20%3D%20%5Cfrac%7B%2810-1%29%5Ctimes%2020%20%2B%2815-1%29%5Ctimes%2030%7D%7B10%2B15-2%7D)
or
= 26.0869
Hence,
the pooled variance will be closer to 30 than to 20
Therefore,
The correct answer is option (a) It will be closer to 30 than to 20