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PtichkaEL [24]
3 years ago
15

Write each improper fraction as a mix numbet 19/4​

Mathematics
1 answer:
anastassius [24]3 years ago
3 0

Answer:

4 3/4

Step-by-step explanation:

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30 secs on battery hurry for brainles
labwork [276]

Answer:

8\frac{1}{2}

Step-by-step explanation:

\frac{17}{2}= 8\frac{1}{2}

17 ÷ 2 = 8.5

8.5 as a mixed number is 8\frac{1}{2}.

3 0
3 years ago
Read 2 more answers
Help pleaseeeee........
VashaNatasha [74]
= 36 x^6 / 9 x^8

= 4 / x^2

Its A
5 0
3 years ago
a family of 6 goes to the local sandwich shop. All six people order the combination meal, which includes a drink and a sandwich
gogolik [260]

Answer:

No, a reasonable estimate is around 6 times $7 = $42

Step-by-step explanation:

$6.99 is rounded up to 7, and there are 6 people who ordered a $7 meal. And 6 times 7 is 42

8 0
2 years ago
Barney & Noblet customers can choose to purchase a membership for $25 per year Members receive 10% off all store purchases
Law Incorporation [45]

Answer:

  1. $70
  2. y = 25 + 0.9x
  3. $250

Step-by-step explanation:

1. 10% of $50 is $5, so the purchases would come to $50 -5 = $45. Added to the $25 membership fee, the total cost for the year would be

  $45 +25 = $70

2. The member pays $25 even if no purchases are made. Then any purchases are 100% - 10% = 90% of the marked price. So, the total is ...

  y = 25 + 0.90x

3. $25 is 10% of $250, so that is the amount the member would have to purchase to break even on cost.

If you like, you can compare the cost without the membership (x) to the cost with the membership (25+.9x) and see where those costs are equal.

  x = 25 +0.9x . . . . . x is the spending level at which there is no advantage

  0.1x = 25 . . . . . . . . subtract 0.9x

  25/0.1 = x = 250 . . . divide by 0.1

4 0
3 years ago
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal
ohaa [14]

Answer: AAA similarity.


Step-by-step explanation:  CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

∠DCE ≅ ∠ACB [same angle]

Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.


8 0
3 years ago
Read 2 more answers
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