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djverab [1.8K]
3 years ago
14

I need help please:):)

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

(0,0)

Step-by-step explanation:

y value divided by x value for slope, then use desmos

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-3 (x+1) as an equivalent expression
Y_Kistochka [10]
-3x-3 is the correct answer
7 0
3 years ago
The area of a rectangular pool is given by the trinomial 2y2 + 5y – 42. What are the possible dimensions of the pool? Use factor
arsen [322]

Answer:

D is your answer

Step-by-step explanation:

(2y-7) (y+6) that is my answer and it matches with D promise 100%

3 0
3 years ago
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
4 years ago
In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.
gulaghasi [49]

Answer:

2.7 square inch

Step-by-step explanation:

\triangle BAC \sim \triangle EDF... (Given) \\

\therefore By area of similar triangle theorem:

\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}

7 0
4 years ago
Hey! i’ll give brainliest please help
Dmitry [639]

Answer:

D

Step-by-step explanation:

hey

8 0
3 years ago
Read 2 more answers
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