Answer:
T₂ = 169.89 K
Explanation:
Given data:
Initial volume = 250 cm³
Initial temperature = 10°C (10+273.15 K = 283.15 K)
Final temperature = ?
Final volume = 150 cm³
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 283.15 K × 150 cm³ / 250 cm³
T₂ = 42472.5 K. cm³ / 250 cm³
T₂ = 169.89 K
Answer:
1000000000000
Explanation:
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Answer:30.27 g HNO3
Step by step solution:
45 g Cu x 1 mol Cu / 63.54 g Cu
= 0.1802 mol Cu
0.1802 mol Cu x 8 mol HNO3/3 mol Cu =0.4805 mol HNO3
Molar Mass HNO3
= 1.0 + 14.0 +3×16.0
= 63.0 g/mol
0.4805 moles HNO3 x 63.0 g HNO3/1 mol HNO3
= 30.27 g HNO3
The acids react with base and the reaction is known as neutralization
One mole of hydronium ion reacts with one mole of hydroxide ion
Here
a) HI is a monoprotic acid : one mole of HI will give one mole of hydronium ion
b) CsOH is a monohydroxide base : one mole of CsOH will give one mole of hydroxide ion
So one mole of HI will react with one mole of CsOH
The moles of CsOH taken will be calculated from molarity and volume as
Thus moles of CsOH are
moles of HI required is 0.005425 mol
volume of HI required will be
Volume of HI required is 9.86 mL
Answer:
D
Explanation:
You should wear goggles whether you are the person performing the experiment or the person watching. Analogy: If someone is using fireworks and they say anyone around should wear ear protection would you wear it if you are next to them?