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MaRussiya [10]
3 years ago
5

What is the mass in grams of 9.45*10^24 molecules of methanol (CH3OH)?

Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0
Number of moles:

1 mole ---------- 6.02x10²³ molecules
? moles --------- 9.45x10²⁴ molecules

1 x ( 9.45x10²⁴) / 6.02x10²³ =

9.45x10²⁴ / 6.02x10²³ => 15.69 moles of CH3OH

Therefore:

Molar mass CH3OH = 32.04 g/mol

1 mole ------------ 32.04 g
15.69 moles -----  mass methanol

Mass methanol  = 15.69 x 32.04 / 1 => 502.7076 g


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Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

<u>Explanation:</u>

Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

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8 0
3 years ago
This stadium can hold 100,000, or 1 x 10^5, people. The number of atoms in a grain of iron is about 1 x 10^18. Would you need 1 
polet [3.4K]
<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

From the question;

1 x 10^5 people can fill 1 stadium

We are given,  1 x 10^18 atoms of iron

We are required to determine the number of stadiums that  1 x 10^18 atoms of iron would occupy.

We are going to assume that a stadium would occupy a number of atoms equivalent to the number of people.

Therefore;

One stadium =  1 x 10^5 atoms

Then, to find the number of stadiums that will be occupied by  1 x 10^18 atoms;

No. of stadiums = Total number of atoms ÷ Atoms in a single stadium

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Therefore,  1 x 10^18 atoms of iron would occupy  1 x 10^13 stadiums

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3 years ago
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D. The number increases and then decreases for noble gases
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Answer:

0.43 mol.

Explanation:

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mass of MgCl₂ = 41.0 g & molar mass of MgCl₂ = 95.211 g/mol.

<em>∴ n = mass/molar mass</em> = (41.0 g)/(95.211 g/mol) = <em>0.43 mol.</em>

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