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3 years ago

12

Please help me with this homework

1 answer:

Leya [2.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

10^2+3^2=109 and sqrt 109 getting 10.4

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What is the value of x?

Dmitriy789 [7]

You have to start with the left triangle and find the side lengths. Since it is a 45-45-90, both sides are the same. Rule for this is hyp= sqrt2 * leg
Since hyp = 6sqrt2, the leg is 6.
The leg is also the hypotenuse of the triangle on the right side.
x is the side across from the hypotenuse and it is the short leg so x = (1/2)6
x = 3

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3 years ago

Stuck On this one too. Think I’m missing a step

Elis [28]

Answer:

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Step-by-step explanation:

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2 years ago

What is 2,252.5327 as a whole numbe<br>

Montano1993 [528]

Answer:

Rounded to the nearest tenth: 2,252.5

Step-by-step explanation:

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2 years ago

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Yanka [14]

Answer:

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3 years ago

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A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago