Answer:
The number of ways can the 3 prizes be awarded = 4 ways
Step-by-step explanation:
It is given that,
There are 4 cyclists in a race. There will be a first place, a second place, and a third place prize awarded.
<u>To find the possible number of ways</u>
There are 4 cyclists
The number of prizes = 3
The number of ways can the 3 prizes be awarded = 4C₃
<u>To find 4C₃</u>
4C₃ = (4 * 3 * 2)/(1 * 2 * 3) = 4 ways
Therefore the number of ways can the 3 prizes be awarded = 4 ways
A = 180 - 143 = 37
b = 143
c = a = 37
e = a = 37
f = 90 - 37 = 53
d = 180 - 85 - 37 = 58
g = 48
h = 180 -48 -48 = 84
k = 180 -84 = 96
m = 180 - 58 - 96 = 26
p = 180 - 26 - 85 = 69
r = 180 -69 = 111
s = p = 69
I can’t see the link but if you resend it I might be able to help