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xxTIMURxx [149]
3 years ago
14

How many molecules are in 0.3903 liters of nitrogen gas?

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

iwan ko mahirap nag tunung

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The volume of a sample of a gas at 273 c is 200.0 l. if the volume is decreased to 100.0 l at constant pressure, what will be th
Lyrx [107]
It will also be halved... but the relationship is with Kelvin not c.  So 273 +273 = 546 K.  half of that is 273 K, then subtract 273... you get 0 degrees c
7 0
4 years ago
The amount of gravitational force impacts the weight of objects.<br> true or false
ElenaW [278]

Answer:

True

Explanation:

It's how gravity works.

8 0
3 years ago
Rank the following 0.100 M solutions in order of increasing H3O+ concentration:
Inessa05 [86]

Answer:

HCN < HOCl < HF  

Explanation:

The larger the Kₐ value, the stronger the acid.

6.2 × 10⁻¹⁰ < 4.0 × 10⁻⁸ < 6.3 × 10⁻⁴

   HCN      <     HOCl    <      HF

 weakest       stronger    strongest

5 0
4 years ago
According to Charles's law, what will happen to the volume of these balloons as temperature
german

Answer:

The volume will decrease and the balloons will be smaller

7 0
3 years ago
It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?
Mnenie [13.5K]

From the calculations, the half life of the material is 6.5 days.

<h3>What is radioactivity?</h3>

The term radioactivity has to do with the spontaneous disintegration of a specie.

Uisng the formula;

N=Noe^-kt

N= amount at time t = 0.135 Ci or 4.995 ×10^9 Bq

No = amount initially present =  1.75 x 10^12 Bq

k = rate constant = ?

t = time taken = 55 days

Hence;

4.995 ×10^9  = 1.75 x 10^12e^-55k

4.995 ×10^9/1.75 x 10^12 = e^-55k

2.85 * 10^-3 = e^-55k

ln2.85 * 10^-3 = -55k

k = ln2.85 * 10^-3/-55

k = 0.1066 day-1

Half life = 0.693/ 0.1066 day-1

= 6.5 days

Learn more about radioactivity:brainly.com/question/1770619

#SPJ1

4 0
2 years ago
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