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2 years ago

3+7+11+15+19+23+271.t1=s1=express t1 in terms of s1

Mathematics

1 answer:

icang [17]2 years ago

8 0

So it would be 3s + 7s + 11s + 15s + 19s + 23s + 27s. Hope this helps

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If a and b are independent events, p(a)=0. 20, and p(b)=0. 80, what is p(b|a)?.

goldfiish [28.3K]

Answer:

P(B | A) = 0.80

Step-by-step explanation:

For independent events A and B, P(B | A) = P(B)

Therefore, P(B | A) = 0.80

3 0

2 years ago

The area of a square slice of cheese is 25 square inches. The perimeter of the slice of cheese is

maxonik [38]

Answer:

As Per Provided Information

Area of given square slice of cheese is 25 square inches .

We have been asked to determine the perimeter of the slice of cheese .

First we will find the side of square slice of cheese .

Let us assume the side of square slice of cheese be s .

Now Let's Solve

$\boxed{\bf \:Area_{(Square)} = {Side}^{2}}$

Substituting the value and we obtain

$\sf \longrightarrow \: 25 = {s}^{2} \\ \\ \\ \sf \longrightarrow \: \sqrt{25} = s \\ \\ \\ \sf \longrightarrow \: s \: = 5 \: inch$

So, the side of square slice cheese is 5 inch

Now let's calculate the Perimeter of cheese

$\boxed{\bf \: Perimeter_{(Square)} = 4 \times side}$

Substituting the value we obtain

$\longrightarrow \sf \: Perimeter_{(Square)} = 4 \times 5 \\ \\ \\ \longrightarrow \sf \: Perimeter_{(Square)} =20 \: inches$

Therefore,

Perimeter of square slice of cheese is 20 inches .

8 0

2 years ago

1 less than the square of a number.

julsineya [31]

Answer: 1 is not a perfect square. 3 is the only prime number one less than a square.

7 0

2 years ago

Danielle runs 1/5 of a mile in 4.5 minutes. if she continues at the same speed, how long will it take her to run two miles?

motikmotik

(1/5) / 4.5 = 2 / m....1/5 mile to 4.5 minutes = 2 miles to m minutes
cross multiply
(1/5)(m) = (2)(4.5)
1/5m = 9
m = 9 * 5/1
m = 45 minutes <===

4 0

3 years ago

Help pleaseee which one

MakcuM [25]

Four more I hoped this helped :)

4 0

2 years ago

3+7+11+15+19+23+271.t1=s1=express t1 in terms of s1​

3+7+11+15+19+23+271.t1=s1=express t1 in terms of s1