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Zolol [24]
3 years ago
14

Select all the situations that describe adding or subtracting opposites to make zero.

Mathematics
2 answers:
jeka943 years ago
4 0
It would be option number 3 and option number 4
ella [17]3 years ago
4 0
It would be 7 decreased by 7 and -7 increased by 7
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The amount of profit, p, you earn by selling knives,k, can be determined by:p=200k-500. A) determine the constraints on profit a
Marizza181 [45]
The only restraints on profit result from the restriction on the domain which in turn place a restriction on profit.  

0≤k. Knives sold cannot be negative.

So the range of profit or p is:

p=[-500, +oo)

Profit increases as the number of knives sold increases.  $200 more profit is gained by each sale of a knife.

4000=200k-500

4500=200k

k=22.5

Since k is for knives sold, it must be an integer value, so a $4000 profit is not possible.  At 22, p=3900 and at 23, p=4100


3 0
3 years ago
Find $y$ if the point $(-6,y)$ is on the line that passes through $(-1,7)$ and $(3,-2)$.
vichka [17]

Answer:

  y = 18.25

Step-by-step explanation:

The 2-point form of the equation of a line can be used to write the equation of the line through the given points.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (-2 -7)/(3 -(-1))(x -(-1)) +7

  y = -9/4(x +1) +7

For x = -6 this evaluates to ...

  y = -9/4(-6 +1) +7 = (9/4)(5) +7 = 45/4 +7

  y = 18 1/4

6 0
3 years ago
Y=-x-4
aliina [53]

Answer:

(-4 , 0)

Step-by-step explanation:

Graph attached

5 0
3 years ago
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

5 0
1 year ago
A teacher writes two equations as shown.
yaroslaw [1]
A) J = (3/8)*(5/15 -6/15) = (3/8)*(-1/15) = (1/8)*(-1/5) = -1/40
.. K = (3/4)*(4/6 -5/6) = (3/4)*(-1/6) = (1/4)*(-1/2) = -1/8

B) (-1/40) +(-1/8) = -1/40 -5/40 = -6/40 = -3/20

C) The opposite of -3/20 is 3/20

D) Real world: I'm answering Brainly.com questions and one asks the opposite of -3/20.
5 0
3 years ago
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