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nikitadnepr [17]

3 years ago

14

A pool can be filled by one pipe in 8 hours and by a second pipe in 2 hours. How long will it take using both pipes to fill the

pool?

1 answer:

andreev551 [17]3 years ago

7 0

let the time taken to be filled by both pipes be y

1/2 +1/8=1/y

(4+1)/8=1/y

5/8=y

cross multiplying

5y=8

y=8/5

=1.6hrs

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mart [117]

Answer:

B. Doubled

Step-by-step explanation:

The formula to find the circumference of the circle is

$C=2\pi r$

Now our problem says that the radius is doubled. Hence the new radius is 2r

Hence the new circumference will be

$C'=2 \pi 2r$

$= 2 \times 2\pi r$

$=2C$

Hence our circumference gets doubled.

3 0

3 years ago

An adult stingray can measure about 350 cm long. how many meters is 350 cm?

Liono4ka [1.6K]

Answer:

<u>3.5 meters</u>

Step-by-step explanation:

1 meter = 100 centimeters

multiply both sides by 3.5 because we are trying to get 350 cm in meters.

1 x 3.5 meters = 100 x 3.5 centimeters

<u>3.5 meters </u>= 350 centimeters

8 0

2 years ago

Marking Brainliest for first right answer

iragen [17]

The answer is 66.63!!!!!!

6 0

3 years ago

Read 2 more answers

Which ones do I circle

bagirrra123 [75]

The first and the third.

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4 0

3 years ago

Read 2 more answers

Find the area enclosed by the graphs of y = sin x, y = cos x, x = 0, and x = 2. Sketch a graph.

mars1129 [50]

Answer:

1.34 (3 sf)

Step-by-step explanation:

To find the area between 2 curves:

$\int\limits^a_b {(top-bottom)} \, dx$

As these 2 curves intersect, we have to first calculate where they intersect, then work out the area between the curves BEFORE and AFTER the point of intersection, as the "top" and "bottom" curves change after the point of intersection (see attached graph).

sin(x) = cos(x)

⇒ tan(x) = 1

⇒ x = $\frac{1}{4} \pi$

So the curves intersect at $x=\frac{1}{4} \pi$ (between x = 0 and x = 2)

To calculate the area between the 2 curves, $x=0$ and $x=\frac{1}{4} \pi$ :

$\int\limits^a_b {(top-bottom)} \, dx=\int\limits^\frac{\pi}{4}_0 {(cos(x)-sin(x))} \, dx=\sqrt{2}-1$

Then to calculate the area between the 2 curves, $x=\frac{1}{4} \pi$ and $x=2$ :

$\int\limits^a_b {(top-bottom)} \, dx=\int\limits^2_\frac{\pi}{4} {(sin(x)-cos(x))} \, dx=0.92106...$

Therefore, the total area = $\sqrt{2} -1+0.92106...=1.335276534...$

(Please Brainliest if helped - thanks!)

6 0

2 years ago