Ask question

Ask question

All categories

nikitadnepr [17]

3 years ago

14

A pool can be filled by one pipe in 8 hours and by a second pipe in 2 hours. How long will it take using both pipes to fill the

pool?

1 answer:

andreev551 [17]3 years ago

7 0

let the time taken to be filled by both pipes be y

1/2 +1/8=1/y

(4+1)/8=1/y

5/8=y

cross multiplying

5y=8

y=8/5

=1.6hrs

You might be interested in

Somebody answer !!!!!

Rainbow [258]

Answer:

D)

Step-by-step explanation:

First we have to subtract 5 from both sides

$\sqrt{x-6} +5=12\\\\\sqrt{x-6}+5-5=12-5\\\\\sqrt{x-6}=7$

Now, square both sides

$(\sqrt{x-6})^{2}=7^{2}$

x - 6 = 49

Now, add 6 to both sides

x - 6 +6 = 49 + 6

x = 55

8 0

3 years ago

ASAP someone please simply two exponents

zhannawk [14.2K]

Answer:

1.) $m^{15}$

2.) $=\frac{1}{y^{15}}$

Give me a comment if you want the explanation.

1.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(m^3\right)^5=m^{3\cdot \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15$

$=m^{15}$

2.) $\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$\left(y^{-3}\right)^5=y^{-3\cdot \:5}$

$=y^{-3\cdot \:5}$

$=y^{-15}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\frac{1}{y^{15}}$

4 0

3 years ago

Evaluate the expression when c=28 and d=7.<br> C+ 49 over d

Ne4ueva [31]

Answer:

11

Step-by-step explanation:

$\frac{c + 49}{7} \\ = \frac{28 + 49}{7} \\ = \frac{77}{7} \\ = 11$

<h2><em>OladipoSeun</em><em>♡˖꒰ᵕ༚ᵕ⑅꒱</em></h2>

6 0

2 years ago

35° (14x + 5)° solution

prohojiy [21]

Answer:

490 + 175

Step-by-step explanation:

35(14+5)

35x14x=490x

35x5=175

490 + 175 = 665x

3 0

2 years ago

Math Help <br> Can you help me <br><br> 4d+6=42

Yanka [14]

4d=42-6
4d=36
d=36:4=9
.....................

4 0

3 years ago

Read 2 more answers