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3 years ago

Does mortality and fertility rates effect human population?

2 answers:

5 0

Yes it effects the human population. If the fertility rate goes down that mean that women aren’t able to produce babies.

fgiga [73]3 years ago

5 0

Answer:

The effect of mortality on population structures is to reduce the component of the population in which the mortality occurs. ... The effect of this is to raise the population in the upper age groups substantially. Women have higher life expectancy than men wherever they live.

Explanation:

Hope this was helpful

You might be interested in

Jupiter's gravity is about 2.3 times stronger than Earth's gravity. Calculate the

AlexFokin [52]

Answer:

Explanation:

There is no change in mass. Therefore, mass = 70 k g

Weight on Jupiter ≈ 1578 N

4 0

3 years ago

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.60 mm. If a

nata0808 [166]

Answer:

Explanation:

(a) For the calculation of the Electric field we use

$E=\frac{V}{d}=\frac{15.0V}{1.6*10^{-3}m} =9375\frac{N}{C}$

(b) The capacitance is calculate by using the expression

$C=\frac{\epsilon_{0}A}{d}=\frac{8.85*10^{-12}C^{2}/(Nm^{2})*(7.6*10^{-4}m^{2})}{1.6*10^{-3}m}=4.2*10^{-12}C$

(c) Finally, the charge on each plate is

$Q=CV=(4.2*10^{-12}C)(15V)=6.3*10^{-11}C$

I hope this is useful for you

Regards

4 0

3 years ago

Read 2 more answers

A conducting rod of mass M with negligible electrical resistance slides on a pair of frictionless, horizontal, parallel, conduct

bixtya [17]

Answer:

Explanation:

Given

mass of rod is M

Distance between rails is L

If the direction of magnetic field is directed upwards

If rod is moving right then,

Area enclosed is increasing therefore a Clockwise current will induce

and if rod is moving left then enclosed area is decreasing therefore an anticlockwise current will setup in the circuit

(b)Induced EMF will be

$E=BvL$

where v=velocity of rod

and current is $I=\frac{V}R}$

$I=\frac{BvL}{R}$

(c)Force necessary to move rod with constant velocity v is

$F_{net}=F-BIL=0$

$F=BIL$

$F=B\times \frac{BvL}{R}\times L$

$F=\frac{B^2L^2v}{R}$

6 0

3 years ago

Two forces P and Q act on an object of mass 15.0 kg with Q being the larger of the two forces. When both forces are directed to

Rom4ik [11]

Answer:

P=6.25N and Q=16.25N

Explanation:

In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).

Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

$\Sigma F=ma$

We can assume there will be only the two mentioned forces P and Q, so

the sum of forces will be:

P+Q=ma

$P+Q=(15kg)(1.50m/s^{2})$

P+Q=22.5N

We can do the same analysis for the second free body diagram:

$\Sigma F=ma$

$Q-P=(15kg)(0.7m/s^{2})$

Q-P=10.5N

so now we have a system of equations we can solve by elimination:

Q+P=22.5N

Q-P=10.5N

Now, we can add the two equations together so the P force is eliminated, so we get:

2Q=32.5N

now we can solve for Q:

$Q=\frac{32.5N}{2}$

Q=16.25N

Now we can use any of the equations to find P.

Q+P=22.5N

P=22.5N-Q

when substituting for Q we get:

P=22.5N-16.25N

P=6.25N

5 0

3 years ago

Convert $25 in dimes<br><br> (I need explanation as well)

CaHeK987 [17]

Answer: To convert this into dimes it's basically like 25 divided by 10.

25 / 10 = 2.5, So you'd need two dimes and a nickel.

7 0

3 years ago