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Nana76 [90]
3 years ago
11

Which of the following pairs of functions are inverses of each other?

Mathematics
2 answers:
Elden [556K]3 years ago
8 0

Answer: A

Step-by-step explanation: A P E X

kherson [118]3 years ago
3 0

Answer:

Proved!

Step-by-step explanation:

For two functions f(x) and g(x) to be inverses of each other then;

f(g(x)) = x and g(f(x)) = x condition must be satisfied.

<u>Checking: A. f(x) = 7x³ + 10 and g(x) = ∛</u>\frac{x - 10}{7}<u />

<u />

So f(g(x)) = 7(\sqrt[3]{(x- 10)/7})³ + 10

We get; 7(\frac{x - 10}{7}) + 10 = x - 10 + 10 = x (*<em>This is correct!)</em>

<em />

So g(f(x)) = \sqrt[3]{((7x^3 + 10) - 10)/7}

Ten cancels out and we are left with;

\sqrt[3]{7x^3/7} = \sqrt[3]{x^3} = x (* <em>This is also correct!)</em>

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Which value for x makes the sentence true?
saul85 [17]

Answer:

x=4

Step-by-step explanation:

3/4x+ 4 = 7

Subtract 4 from each side

3/4x+ 4-4 = 7-4

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3 years ago
Helpp me out pls!!!!!!!!!
dsp73

Answer:

a. Maurice walked farther.

b. 0.62 m

Step-by-step explanation:

Maurice

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2.5 × 3.2 = 8 miles

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disa [49]

Answer:

QRT = 47, TRS = 133

Step-by-step explanation:

Since QRS is a line, QRT + TRS = 180.

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Then, solve for x. Combine like terms.

13x-2=180\\13x=182\\x=14

Then, plug in 14 for x.

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Can someone help me with these questions? i’m so lost
spayn [35]

Answer:

Q.5 ab=cd

Q.6 ad=bc

Q.7 ce=ae

Q.8 eb=ed

Q.9 angle D=angle B (opposite angle of parallelogram are equal)

let other angle of parallelogram be x.

angle A+angle B +angle C + angle D= 360° (sum of quadrilateral is 360°)

x+130°+x+130°=360°

2x+260°=360°

2x=360°-260°

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2x=238°

x=238°/2

x=119°

Q.11 in quadrilateral opposite angles are equal and opposite angle of parallelogram are equal.

Q.12 in quadrilateral opposite angle are equal and opposite angle of parallelogram are equal.

Q.13 in quadrilateral opposite sides are equal and opposite sides are parellel and this property is also present in parallelogram.

q.14 in quadrilateral diagonal bisected each other and diagonal of parallelogram also bisect each other.

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