Find an angle 0 coterminal to 904°, where 0° < 0 < 360°
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Ok so for slope it's difference in y dividing by the difference of x. The difference of y is 10 - 6 which is 4, and the change in x is 5 - (-3) which is 8. Dividing 4 by 8 gets us 1/2. So the slope is 1/2. Slope intercept form would be y = mx + b, and the slope is 1/2 so it'd be y = (1/2)x + b. Plug in a point and you get b = 15/2. So the final slope intercept form would be y = (1/2)x + 15/2. For point slope form just put in a point and slope and you get y - 6 = (1/2) × (x + 3). Standard form would have to be arranged from slope intercept. So multiplying 2 to the slope intercept form we get 2y = x + 15. Subtracting x we get -x + 2y = 15. In standard form we don't want x to be negative so just multiply by negative one and we get x - 2y = -15.
