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UkoKoshka [18]
3 years ago
12

Find the mean of the following data: 0, 5, 30, 25, 16, 18, 19, 26, 0, 20, 28

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

17

Step-by-step explanation:

In order to find a mean in a data set you need to be able to add all numbers provided than divided them by the numbers given. which in this case

- 0+5+30+25+16+18+19+26+0+20+28= 187

- There are 11 number given so we take:

187/11

187/11= 17

Have a nice day!

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A box contains 23 transistors,6 of which are defective. If 6 are selected at random, find the probility that none are defective
ipn [44]
|\Omega|=C(23,6)=\dfrac{23!}{6!17!}=100947\\
|A|=C(17,6)=\dfrac{17!}{6!11!}=12376\\\\
P(A)=\dfrac{12376}{100947}=\dfrac{1768}{14421}
3 0
4 years ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
3 years ago
12.6% of<br>RI 149 390bn​
galina1969 [7]

Answer: RI 18,823.14

Step-by-step explanation:

I guess that we want to find the 12.6% of Rl 149,390

First, we assume that Rl 149,390 is the 100%

Then we can write an equation like:

Rl 149,390 = 100%

Then if the amount X is the 12.6%, we also have the equation:

X = 12.6%

Then we have the two equations:

X = 12.6%

Rl 149,390 = 100%

If we take the quotient between these two equations we get:

(X/Rl 149,390) = (12.6%/100%)

Solving this for X we get:

X =  (12.6%/100%)*(Rl 149,390) = RI 18,823.14

7 0
3 years ago
SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!
nadezda [96]

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal  ( 2a  = 3b+2  and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a  = 3b+2

Substitute in b=2

2a = 3(2) + 2

2a = 6+2

2a =8

Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

    = 2(4) + 3(2)+2

   = 8+6+2

   = 16

FH = 2a+3 + 6b-1

    = 2(4) +3 +6(2)-1

    = 8+3+12-1

   = 23-1

  = 22

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3 years ago
Need help with 17 pre college
Ratling [72]
No because if you plug in 4 for x and 5 for y you get -4 not 36
6 0
2 years ago
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