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gizmo_the_mogwai [7]
3 years ago
9

Write a program that takes a positive integer argument N, and prints out the average, minimum, and maximum (in that order) of N

uniform random numbers that it generates. Note that all three statistics should be over the same sequence of N random numbers python
Computers and Technology
1 answer:
Flura [38]3 years ago
7 0

Answer:

from random import seed, choices

from statistics import mean

number = int(input("Enter integer number: "))

if number > 0:

   try:

       data = range(number+1)

       # to generate a pseudo-random number list.

       seed(10)

       # you can also use: num_list = [random.randint(0, number+1) for i in data]

       num_list = choices(data, k=len(data))

       print(num_list)

       mean_val = round(mean(num_list), 2)

       min_val = min(num_list)

       max_val = max(num_list)

   except ValueError:

       print("Must be an integer value.")

print('Avg number: {}\nMax number: {}\nMin number: {}'.format(mean_val, max_val, min_val))

Explanation:

To generate random items in a list of integers, the random choices method is used and a sequence is passed as an argument. The average, maximum, and minimum number of the list is calculated and displayed.

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Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:
ArbitrLikvidat [17]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 

 System.out.print("Enter a number: ");

 int userVal = input.nextInt();

 

 String aString;

 if(userVal < 0)

     aString = "negative";

 else

     aString = "non-negative";

     

 System.out.println(aString);

}

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

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meriva

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Answer:

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