One mole contains 6.022×10^23 actually
Answer:
pH = 8.48
Explanation:
HOBr dissociates in water as follows:
- HOBr(aq) ↔ H⁺(aq) + OBr⁻(aq)
With a ka expressed by:
- ka = [H⁺]*[OBr⁻] / [HOBr]
We rearrange and <u>solve for [H⁺]</u>:
- [H⁺] = ka * [HOBr] / [OBr]
Because the volume is 1 L, the moles added of HOBr and KOBr (OBr⁻) are also the molar concentration:
- [H⁺] = 2.0x10⁻⁹ * 0.50 / 0.30
Finally we <u>calculate the pH</u>:
Answer:
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Explanation:
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