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Alecsey [184]
2 years ago
14

George operates a fishery. Last month, he noticed that the number of fish had decreased. Which discipline can provide valuable i

nformation to an environmental scientist to help solve George's problem?
Chemistry
2 answers:
Solnce55 [7]2 years ago
8 0

Answer:

Fisheries science. This discipline aims to study and understand fisheries biology, food web, the predator-prey relationship, stock status information, as well as the socioeconomic status of fishermen (commercial and substantial)

Explanation:

The information from this discipline will help environmental scientists understand why there is a decrease in fish in the ocean. The reasons can vary from over fishing to decline in the reproduction of fishes due to climate change.

omeli [17]2 years ago
4 0

Answer:the Field of AGRICULTURAL SCIENCE can Help Solve The Problem. It is a broad field that involves the study of AGRICULTURAL Resources, such as forest, crops,and fusheries

Explanation:

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A sample of ammonia ^NH3h gas is completely decomposed to nitrogen and hydrogen gases over heated iron wool. If the total pressu
icang [17]

Answer : The partial pressure of N_2 and H_2 is, 216.5 mmHg and 649.5 mmHg

Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

p_i=X_i\times p_T

X_i=\frac{n_i}{n_T}

So,

p_i=\frac{n_i}{n_T}\times p_T

where,

p_i = partial pressure of gas

X_i = mole fraction of gas

p_T = total pressure of gas

n_i = moles of gas

n_T = total moles of gas

The balanced decomposition of ammonia reaction will be:

2NH_3\rightarrow N_2+3H_2

Now we have to determine the partial pressure of N_2 and H_2

p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T

Given:

n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg

and,

p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T

Given:

n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg

p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg

Thus, the partial pressure of N_2 and H_2 is, 216.5 mmHg and 649.5 mmHg

5 0
3 years ago
7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0
2 years ago
Read 2 more answers
A piece of iron can change in different ways. How is iron bending different from iron rusting
fenix001 [56]
Iron bending is just a physical change because the iron has only changed shape but there is no new substance. Iron rusting is a chemical change because there is a new substance which is rust.
7 0
3 years ago
Identify each definition that applies to the compound in red. Check all that apply.
andre [41]

Answer:

Arrhenius acid & Bronsted-Lowry acid

Explanation:

4 0
3 years ago
Nitrogen and oxygen form an extensive series of oxides with the general formula NxOy. One of them is a blue solid that comes apa
Marizza181 [45]

Work out the number of moles in

100.00 grams of the oxide.

For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:

36.84 g N14.0067 g N/mol N=2.630 mol N

For oxygen: The atomic mass of O is

15.9994, and we have

100.00−36.84=63.16 g O:

63.16 g N 15.9994 g N/mol N=3.948 mol N

Now the ratio 3.958 2.630 is very close to

1.5=32

. So we conclude that the gas has three moles

O to two moles N making the empirical formula

N2O3.

<h2><u>Mark as Brainliest</u></h2>
5 0
2 years ago
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