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Yakvenalex [24]
3 years ago
13

The density of aluminum is 2.70 g/cm'. If the volume of a piece of aluminum is 90.4 cm', what is

Chemistry
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

33.4814814815

Explanation:

90.4/2.70

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suppose that recording station N located 200 km north of the epicenter of an earthquake, and recording station S is located 100
andrezito [222]

Answer:

c.The value of T at Recording Station N would be greater than T at Recording Station S.

Explanation:

We can deduce from the information provided that the value of T at recording station N would be greater than T at recording station S.

This problem relates distance with time.

       Speed  = \frac{disance}{time}

                  Distance  = Speed x time

  • Just like any other physical quantity, speed of a substance is directly related to time.
  • The larger the time taken the farther the distance it will cover assuming the velocity is constant.
  • Earthquake waves for example moves at constant speed with a unique velocity in earth materials.
  • The farther the distance, the more time it will take to reach the seismic recording station.
  • Since N is a distance of 200km from the epicenter, it will take a greater time and have a higher reading of T to reach the station.
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3 years ago
38 POINTS - PEER COUNSELING 2 QUESTION
brilliants [131]

anything except for a and d

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3 years ago
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Which of the following measurements has three significant figures?
Free_Kalibri [48]

The correct answer is <u>C: 0.510 m</u>

<u></u>

N I C E - D A Y!

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2 years ago
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Need asap thank you
cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

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2 years ago
How many moles are in 10 mg of NO2
podryga [215]

mole=10 x 10⁻³ : 46 g/mol = 2.17 x 10⁻⁴

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2 years ago
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