Answer:
B. 67.6/Hg(200.5)= .337. 10.8/S(32.1)= .336. 21.6/O(16)= 1.35--> .337/.336= 1 .336/.336= 1 1.35/.336= 4. Formula= HgSO4
Explanation:
Answer:
A) The shared electrons in C-O bonds spend less time close to the carbon nucleus than the shared electrons in C-H bonds.
Explanation:
The electronegativity from H is 2.2, from C is 2.55 and from O is 3.44. This property is the measure of the attractive force between an atom and a pair of electrons.
So, the difference of electronegativity of H and C is smaller than the difference between O and C. Because oxygen is more electronegative, the electrons stay close to it in the bond C=O. So carbon has a partial positive charge in that bond. For the bond C-H, the shared electrons stay closes to carbon.
Answer:
CH₄
+ 2O₂
→ CO₂
+ 2H₂O![_{(g)}](https://tex.z-dn.net/?f=_%7B%28g%29%7D)
Explanation:
This kind of reaction in which a hydrocarbon combines with oxygen gas is a combustion reaction. They are mostly used to produce heat energy that can be transformed into other forms of energy.
Every chemical reaction is made up of reactants and products. The combining species on the left hand side are the reactant and the products are the result of the combination.
Note: in writing chemical equations, the state of matter must always be included.
Reactants : Methane gas CH₄
Oxygen gas O₂
Product: Carbon dioxide CO₂
Water vapor H₂O
CH₄
+ 2O₂
→ CO₂
+ 2H₂O![_{(g)}](https://tex.z-dn.net/?f=_%7B%28g%29%7D)
Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (
), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that
and
, then the eccentricity of the ellipse is:
![e = \frac{5.2}{20.6}](https://tex.z-dn.net/?f=e%20%3D%20%5Cfrac%7B5.2%7D%7B20.6%7D)
![e = 0.252](https://tex.z-dn.net/?f=e%20%3D%200.252)
The eccentricity of the ellipse is 0.252.