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makvit [3.9K]
3 years ago
14

Solve: please answer as fast as possible -2 + 6 < 4

Mathematics
2 answers:
Marat540 [252]3 years ago
8 0
-2+6=4\\\\therefore\ -2+6 \ \textless \  4\ is\ false\\\\&#10;This\ inequality\ will\ be\ correct\ if\ sign\ of\ inequality\ will\ be:"\leq"\\\\\huge\boxed{-2+6\leq4}
Naya [18.7K]3 years ago
4 0
-2 + 6 < 4 equals 4 < 4.

First, simplify -2 + 6 to get 4. / Your problem should look like: 4 < 4.

If you are looking for the solution to this problem, there is none since 4 < 4 is false.

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This is 4x=2x-2 as a graph

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den301095 [7]

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3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

7 0
11 months ago
Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

#SPJ9

5 0
1 year ago
15-3+2<br> What’s the answer and why?
Charra [1.4K]

Answer:

10

Step-by-step explanation:

Apply the DMAS rule.

3 0
3 years ago
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