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3 years ago

Solve: please answer as fast as possible -2 + 6 < 4

2 answers:

8 0

$-2+6=4\\\\therefore\ -2+6 \ \textless \ 4\ is\ false\\\\
This\ inequality\ will\ be\ correct\ if\ sign\ of\ inequality\ will\ be:"\leq"\\\\\huge\boxed{-2+6\leq4}$

Naya [18.7K]3 years ago

4 0

-2 + 6 < 4 equals 4 < 4.

First, simplify -2 + 6 to get 4. / Your problem should look like: 4 < 4.

If you are looking for the solution to this problem, there is none since 4 < 4 is false.

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<u>Given equation</u>:

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Factor out the coefficient of the x² term and the y² term.

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Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

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Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

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co-vertices = (1, 0) and (1, 4)
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