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PSYCHO15rus [73]
2 years ago
8

Given the following table, which statement is true about atoms A and B

Chemistry
1 answer:
Aloiza [94]2 years ago
6 0
Im sorry you didnt ss the table?
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What should a simplified model of a large molecule like glucose show?
maxonik [38]

Glucose is the simplest sugar and carbohydrate that provides energy. The simplified model of glucose (C₆H₁₂O₆) shows carbon, hydrogen, and oxygen atoms linked together.

<h3>What is glucose?</h3>

Glucose is an example of a carbohydrate macromolecule that is further classified as a monosaccharide. They are crystalline and fundamental units of carbohydrates.

The molecular formula of glucose is C₆H₁₂O₆ and the mass is 180.156 g/mol. It is an aldohexose that contains an aldehydic functional group. In its structure, there are six oxygen atoms, six carbon atoms, and twelve hydrogen atoms.

Therefore, the glucose molecule is composed of C, H, and O.

Learn more about glucose here:

brainly.com/question/2396657

#SPJ1

5 0
1 year ago
Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid (H2C2
belka [17]

Answer:

Oxalic acid is a dicarboxylic acid and forms sodium salt with NaOH and water

Explanation:

4 0
3 years ago
Read 2 more answers
If the air temperature is the same as the temperature of your skin (about 30◦C), your body cannot get rid of heat by transferrin
Elenna [48]

Answer:

Explanation:

a )

energy produced per second = 500 J

Heat produced = 500 x .8 = 400 J per second.

If m be the mass of water evaporated per unit hour

m x latent heat = 400 x 60 x 60

= m x 2.42 x 10⁶ = 1.44 x 10⁶

m = .595 kg per hour

b )

volume of water = 595 mL

bottles = 595 / 750

.8 or 4/5 of bottle. per hour.

8 0
3 years ago
A total of 663 cal 663 cal of heat is added to 5.00 g 5.00 g of ice at − 20.0 °C . −20.0 °C. What is the final temperature of th
Serjik [45]

Answer:

Final Temperature = 305.9 K or 32.9°C

Explanation:

Information given;

Mass (m) = 5g

Amount of Heat (H) = 663 calories

Initial Temperature = -20°C + 273 = 253K (Converting to Kelvin Temperature)

Final Temperature?

Specific Heat capacity of Water (c) =?

One might probably rush to use H = m * c * (T2-T1) to calculate the fianl temperature. That would have been wrong because Ice would melt when heat is being applied to it. And using that formular directly would lead to not considering the amount of heat required to melt it.

First let us check the amount of heat required to raise the temperature of the ice to 0°C

In this case now; Final temperature = 0°C + 273 = 273 K (Converting to Kelvin)

H = m * c * (T2-T1)

H = 5 * 1 * (273 - 253)

H = 5 * 1 * 20 = 100 cal

This shows the heat supplied is enough (663 cal is more than 100 cal) to bring the ice to its melting point.

Let's see if it would be sufficient to melt it.

Amount of Heat required to Melt ice;

H = mL;

where L = heat of fusion = 79.7 cal/g

H = 5 * 79.7 = 398.5 cal

Again, the heat is sufficient to melt it; the remaining heat would be used in raising the temperature of the liquid water.

In this case, initial temperature = 0°C + 273 = 273 K (Converting to Kelvin)

Amount of Heat left = 663 - 398.5 - 100 = 164.5 cal

Final temperature is given as;

H = m * c * (T2-T1)

164.5 = 5 * 1 * (T2 - 273)

T2 - 273 = 164.5 / 5

T2 = 273 + 32.9 = 305.9 K

Final Temperature = 305.9 K or 32.9°C

4 0
3 years ago
What is the pun when I go from here to there quickly on foot
zlopas [31]
1. A type of mens cologne
2. A police officers boss
3. When i go from here to there quickly on foot

Idk thats what google said
6 0
3 years ago
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