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3 years ago

What type of elements generally bond covalently, and how do they satisfy the octet rule?

Chemistry

1 answer:

Alex Ar [27]3 years ago

3 0

Answer:

Covalent, or, elements on the right side of the ladder (on the periodic table). Covalent compounds satisfy the octet rule by sharing electrons.

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The molar volume of oxygen,O2, is 3.90 dm3 mol-1 at 10.0 bar and 200 degree centigrade. Assuming that the expansion may be trunc

schepotkina [342]

Answer:

B = - 0.0326 dm³/mol

Explanation:

virial eq until second term:

PVm = RT [ 1 + B/Vm ]

∴ P = 10 bar * (atm/ 1.01325 bar) = 9.869 atm

∴ T = 200°C = 473 K

∴ Vm = 3.90 dm³/mol

∴ R = 0.08206 dm³.atm/K.mol

⇒ PVm / RT = 1 + B/Vm

⇒ ((9.869 atm)*(3.90 dm³/mol)) / ((0.08206 dm³.atm/mol.K)*(473K)) = 1 + B/Vm

⇒ 0.99164 = 1 + B/Vm

⇒ B/Vm = - 8.357 E-3

⇒ B = (3.90 dm³/mol)*( - 8.357 E-3 )

⇒ B = - 0.0326 dm³/mol

4 0

3 years ago

3. A 3.455-g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of

erik [133]

Answer:

$Ba\ percentage\ in\ Mass=4.8\%$

Explanation:

From the question we are told that:

Mass of mixture $m=3.455g$

Mass of Barium $m_b=0.2815g$

Equation of Reaction is given as

$Ba2+ + H2SO4 => BaSO4 + 2 H+$

Generally the equation for Moles of Barium is mathematically given by

Since

$Moles of Ba^{2+} = Moles of BaSO_4$

Therefore

$Moles of Ba^{2+} = \frac{mass}{molar mass of BaSO4}$

$Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol$

Generally the equation for Mass of Barium is mathematically given by

$Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}$

$Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g$

Therefore

$Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%$

$Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%$

$Ba\ percentage\ in\ Mass=4.8\%$

8 0

3 years ago

What Went Wrong – Balancing Chemical Equations

OLEGan [10]

1-It has to be 3 Fe and not Fe3.
2-The oxygens aren't balanced

Balanced equation:
3Fe+4H2O---->Fe3O4+4H2

4 0

3 years ago

(You do) If you have 47.2 mol of Na available, along with an excess of Cl₂, how many grams of NaCl can you produce?

IrinaVladis [17]

Answer:

2,760 grams NaCl

Explanation:

To find grams of NaCl, you need to (1) convert moles of Na to moles of NaCl (via mole-to-mole ratio from reaction) and (2) convert moles of NaCl to grams (via molar mass from periodic table). The final answer should have 3 significant figures based on the given measurement.

2 Na + Cl₂ --> 2 NaCl

Molar Mass (NaCl) = 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl) = 58.44 g/mol

47.2 moles Na 2 moles NaCl 58.44 grams

---------------------- x --------------------------- x ------------------------- =
2 moles Na 1 mole NaCl

= 2,758.368 grams NaCl

= 2,760 grams NaCl

5 0

1 year ago

Which of the following is an example of translational kinetic energy? windmill a tuning fork a person running a car parked in a

Hatshy [7]

a person running a car parked in a driveway

Explanation:

A person running a car parked in a driveway is an example of translational kinetic energy.

Translational motion is the movement of body along a straight path.

Translational kinetic energy refers to the energy of a body moving along a straight path.

It is function of the mass and velocity of the moving body.
The motion of train on its track is an example of this form of energy
A fired bullet, falling object all experience translational kinetic energy.

learn more:

Translational kinetic energy brainly.com/question/9924094

#learnwithBrainly

3 0

3 years ago

Read 2 more answers