Answer:
a) 52.8
Explanation:
M1V1 = M2V2
(7.91 M)(x ml) = (2.13 M)
(196.1 ml)
(7.91M) (xml) = 417.693 M.ml
x ml = 417.693/ 7.91
x = 52.8
25% of 20
%=100
25/100 x 20
1/4 x 20
The answer is equal to 5
The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .
The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure V= volume and T = temperature.
From ideal gas equation
P₁V₁/T₁ =P₂V₂/T₂
105×220÷275 = P₂ ×95÷310
P₂= (105×220×310)÷(275×95)
P2= 7161000/26125
P2 = 274.105 kPa
Hence, the new pressure of helium gas is 274kPa
To know more about Ideas gas equation
brainly.com/question/28837405
#SPJ1
Use the ICE table approach as solution:
PbSO₄ --> Pb²⁺ + SO₄²⁻
I - 0 0
C - +s +s
E - s s
Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = <em>1.35×10⁻⁴ M</em>
I believe the answer is orbital hybridization theory
