Answer:
Molarity of solution = 0.727M
Explanation:
Molarity of solution is defined as moles solute per Liter of solution. For the posted problem use M = n/V where n = moles of solute and V = Liters of solution. That is ...
n = 58.9g/180.16g·mole⁻¹ = 0.327 mole (3 sig. figs.)
V = 450.0ml/1000ml·L⁻¹ = 0.450L (3 sig. figs.)
∴ Molarity = n/V = 0.327mole/0.450L = 0.727mol/L = 0.727M
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Innovated Understanding Curious Logical
Answer:
Qm = -55.8Kj/mole
Explanation:
NaOH(aq) + HNO₃(aq) => NaNO₃(aq) + H₂O(l)
Qm = (mc∆T)water /moles acid
Given => 100ml(0.300M) NaOH(aq) + 100ml(0.300M)HNO₃(aq)
=> 0.03mole NaOH(aq) + 0.03mole HNO₃(aq)
=> 0.03mole NaNO₃(aq) + 0.03mole H₂O(l)
ΔH⁰rxn = [(200ml)(1.00cal/g∙°C)(37 – 35)°C]water / 0.03mole HNO₃
= 13,333 cal/mole x 4.184J/cal = 55,787J/mol = 55.8Kj/mole (exothermic)*
Heat of reactions comes from formation of H-Oxy bonds on formation of water of reaction and heats the 200ml of solvent water from 35⁰C to 37⁰C.
