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Zina [86]
3 years ago
8

Does a melted iceberg increase the salinity of the ocean?

Chemistry
2 answers:
SSSSS [86.1K]3 years ago
8 0
Hello @andoo5,

How are you doing? Icebergs are made up of fresh water. No salt (:. Which means when it melts into the salty water, you have lower levels of salinity. I hope this helps! 

Thank you,
Darian D. 
antiseptic1488 [7]3 years ago
7 0
Dedpool here!

no it doesn't

hope this helps

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Consider the following equilibrium:
irga5000 [103]

Consider the following equilibrium:

4NH₃ (g) + 3O₂ (g) ⇄ 2N₂ (g) + 6H₂O (g) + 1531 kJ

The given statement is True, because

According to Le Ch's Principle:

Systems that have attained the state of chemical equilibrium will tend to maintain their equilibrium state.

External factors such as the addition of products and reactants result in the disruption of the equilibrium state.

we expect the system to shift to the direction that offsets the change in concentration.

This results in the state of chemical equilibrium to be reestablished.

Hence, The statement is true,

  • The addition of more ammonia (a reactant) would offset the state of equilibrium.
  • To restore chemical equilibrium, the system must consume the excess reactants to form more products.
  • A shift to favor the products side occurs.

To learn more about equilibrium here

brainly.com/question/3920294

#SPJ4

8 0
1 year ago
What is the molality of a solution of Fe(ClO3), in water that freezes at -2.72°C?
Anon25 [30]

Answer:

0.366m = Molality of the solution

Explanation:

To solve this question we must know the addition of a solute produce decreasing in freezing point regard to the pure solvent. The equation is:

ΔT = m*Kf*i

<em>Where ΔT is change in freezing point </em>

(As freezing point of water is 0°C, the ΔT is 2.72°C)

<em>Kf is freezing point depression constant = 1.86°C/m for water</em>

<em>i is Van't Hoff factor. The number of ions produced when 1 mole of the salt is dissolved = 4 ions for Fe(ClO₃)₃, Fe³⁺ and 3 ClO₃⁻ ions</em>

<em>m is molality of the solution.</em>

<em />

Replacing:

2.72°C = m*1.86°C/m*4

<h3>0.366m = Molality of the solution</h3>

<em />

3 0
3 years ago
A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al
Musya8 [376]

Answer:

The value of K_p is 0.02495.

Explanation:

Initial concentration of SCL_2 gas = 0.675 M

Initial concentration of C_2H_4 gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)

initially

0.675 M            0.973 M        0

At equilibrium ;

(0.675-0.35) M            (0.973-2 × 0.35) M        0.35 M

The equilibrium constant is given as :

K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}

=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}

K_c=14.45

The relation between K_p and K_c are :

K_p=K_c\times (RT)^{\Delta n}

where,

K_p = equilibrium constant at constant pressure = ?

K_c = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

\Delta n = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}

K_p=6.2\times 10^{4}

K_p=0.02495

The value of K_p is 0.02495.

7 0
3 years ago
Three chemical reactions of ethane?
Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0
3 years ago
Why do you del cold when you get out of the pool?
Vera_Pavlovna [14]
The water on your skin is evaporating, pulling heat with it. This is  called evaporative cooling.
6 0
3 years ago
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