Answer:
10.7 g of KOH
Explanation:
First of all, we determine the reaction:
2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)
We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles
Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.
We convert the moles to mass, to finish the answer:
0.192 mol . 56.1g /1mol = 10.7 g of KOH
From the equation:
1 mole Fe₂O₃ needs 3 moles of CO
1.75 moles require:
1.75 x 3
= 5.25 moles of CO
Mass of water added:
0.997 x 1500
= 1495.5 grams
a) Volume = mass / density
Volume = 1495.5 / 0.917
Volume = 1630 cm³ = 1.63 L
b) The ice cannot be contained in the bottle as its volume exceeds that of the bottle.
A double bond between carbon atoms is longer than a triple bond between carbon atoms.
