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maw [93]
2 years ago
15

Which statement best defines the term innate behavior?

Chemistry
2 answers:
son4ous [18]2 years ago
6 0

Answer: behavior that is simple, untaught, and born knowing

Have a nice dam day!!

Murrr4er [49]2 years ago
4 0

Answer:

The Answer is gonna be behavior that is simple, untaught, and born knowing:3

<em> I hope you are having a great day</em> ❤️

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What are similarities and differences between ionization energy and electron affinity
Vladimir [108]
Ionization energy: the energy required to remove an electron from a neutral atom. Electron affinity: the energy change when a neutral atom attracts an electron to become a negative ion.
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3 years ago
Ed records the temperature of two pots of water. Pot X has a temperature of 56 degrees Fahrenheit, and pot Y has a temperature o
7nadin3 [17]

Answer:

Itś A) The water in pot X has more kinetic energy than the water in pot Y.

Explanation:

Did it on a quiz

ed2020

6 0
3 years ago
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Sam investigates the reactivity of metals in air. His observations are shown below.
viva [34]

Answer:5

Explanation:

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2 years ago
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During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
2 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
2 years ago
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