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Mandarinka [93]
3 years ago
7

3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.​

Chemistry
1 answer:
-BARSIC- [3]3 years ago
8 0

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\

Thus, by performing the division we obtain:

12.7molNa

Regards!

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Answer:

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8 0
3 years ago
Dissolving 4.02 g of CaCl2 in enough water to make 349 mL of solution causes the temperature of the solution to increase by 3.91
gregori [183]

Answer:

ΔH per mole of CaCl2 is 160.3 kJ

Explanation:

<u>Step 1: </u>The balanced equation

CaCl2 (aq)→  Ca2+  +  2Cl-(aq)

<u>Step 2:</u> Data given

Molar mass of CaCl2 =110.98 g/mole

mass of CaCl2 = 4.02 grams

volume of the solution = 349 mL = 0.349 L

Temperature increases with 3.91 °C

Specific heat of the solution = specific hea of water = 4.18 J/°C*g

Density solution = density water = 1g/cm³

<u>Step 3:</u> Calculate moles of CaCl2

Numer of moles of CaCl2 = mass of CaCl2 / Molar mass of CaCl2

Number of moles = 4.02 grams /110.98 g/mole= 0.036 moles

<u>Step 4</u> = Calculate amount of heat added

Q = m*c*ΔT

with m = the mass 349 grams + 4.02 grams = 353.02 grams

c = 4.18 J/°C*g

ΔT = 3.91 °C

Q = 353.02*4.18*3.91 = 5769.69 J

Step 5: Calculate ΔH per mole

5769.69 J /0.036 moles = 160269.1 J = 160.3 kJ

ΔH per mole of CaCl2 is 160.3 kJ

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