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3 years ago

If P(x)=x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)

Mathematics

2 answers:

juin [17]3 years ago

4 0

Answer:

(x2 – 1) – 5(x – 1)

Step-by-step explanation:

C) ED2020

soldier1979 [14.2K]3 years ago

3 0

All you need to do $p(x)-q(x)$ . So:

$(x^{2}-1)-(5)(x-1)$

That's it!

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Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Social Security tax that is 6.2% of his gross pay Medicare tax that is 1.45% of his gross pay state tax that is 19% of his feder

Olegator [25]

Answer:

option d

Step-by-step explanation:

6 0

2 years ago

Please help!! I don’t get it

Marrrta [24]

Answer:

Each hotdog costs $1.65

Each juice drink costs $1.05

Step-by-step explanation:

Let's begin by letting $x$ represent the number of hot dogs and $y$ the number of juice drinks.

The Baxter family bought 6 hot dogs and 4 juices for $14.10.

$6x + 4y = 14.10$

The Farley family bought 3 hot dogs and 4 juices for $9.15.

$3x + 4y = 9.15$

Now, we subtract these equations.

$6x + 4y = 14.10\\- (3x + 4y = 9.15)$

Since $y$ has reversed coefficients, it gets eliminated. Now solve for x.

$6x+4y-3x-4y=14.1-9.15\\3x = 4.95\\\frac{3x}{3} = \frac{4.95}{3}$

$\frac{4.95}{3} = 1.65$

$x = 1.65$

NOW, we find y by substituting x with 1.65 (in either equation).

We'll use the first equation.

$6x + 4y = 14.10$

$6(1.65) + 4y = 14.10$

$9.9 + 4y = 14.10\\4y = 14.1 - 9.9\\4y = 4.2$

$\frac{4y}{4} = \frac{4.2}{4} \\y = 1.05$

$x$ = 1.65

$y$ = 1.05

$x$ represents hotdogs and $y$ represents juice drinks.

Therefore, each hotdog costs $1.65 and each juice drink costs $1.05.

<em> I hope this helps! :)</em>

6 0

3 years ago

What is three fourths the square of b

lana [24]

Simplifying it would make it 3/4b^2. I can't write it down the correct way, but it's three over four times b squared. Unless it's a square root, then things would be different.

4 0

3 years ago

is the first one proportional or nonproportional. And is the fist one proportional or nonproportional.

vichka [17]

Nonprportional is what I would think

3 0

3 years ago