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Dmitry [639]
3 years ago
6

Please help me with this

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer: slope = 4

Step-by-step explanation:

slope = m = rise/run = y1-y2/x1-x2

9-1/5-3 = 8/2 = 4

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The Andrews Family bought 2 adult tickets,3 children tickets,and 1 senior
kirill [66]

Answer:

$26.00

Step-by-step explanation:

6 0
3 years ago
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Pleaseee helppp!!! I'll give brainliestt!!<br><br> AND<br> please don't just answer for points!
kvasek [131]

Answer:

x=-8 where A=1 and B=0

Step-by-step explanation:

The given line's graph is x=-8. Since there is no y, they coefficient in front of y, B, will be 0, and since there is only one x, that coefficient in front of the x, A, will be 1.

5 0
3 years ago
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Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.)
Salsk061 [2.6K]

Answer:

Mix fraction: 3 1/27

Improper fraction: 82/27

Decimal approximation: 3.037

Step-by-step explanation:

What value is close to 28 that is a perfect cube...27 which equals 3^3.

So let's find the tangent line to the curve y=cubert(x) at x=27.

We will use this equation to approximate what happens at x=28.

First let's rewrite the radical in our equation;

y=x^(1/3)

Now differentiate

y'=(1/3) x^(1/3-1) by power rule

Simplify

y'=(1/3) x^(-2/3) or (1)/(3x^[2/3])

So the slope of our tangent line at x=27 is (1)/(3(27)^[2/3])=1/(3(3)^2)=1/(3×9)=1/27.

We will also need a point on this tangent line....We know we have the point at x=27 because that is what our tangent line to curve is being found at.

So at x=27, we have y=cubert(27)=3. We used our equation y=cubert(x) here.

So we want to find the equation of the line that contains point (27,3) and has slope 1/27.

Point-slope form is

y-y1=m(x-x1)

Plug in our values

y-3=(1/27)(x-27)

Add 3 on both sides

y=3+(1/27)(x-27)

We will use this linear equation to approximate cubert(28) by replacing x with 28.

y=3+(1/27)(28-27)

y=3+(1/27)(1)

y=3+1/27

You can write that as a mix fraction if you want.

This value is than 3 but super close to 3 since 1/27 is close to 0.

Mix fraction: 3 1/27

Improper fraction: 82/27

Decimal approximation: 3.037

Cubert of 28 when smashed into calculator as is gives approximately 3.0366 which is pretty close to our approximation.

4 0
3 years ago
Read 2 more answers
Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph
Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


1\le x\le 2


f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



4 0
3 years ago
What value of x is in the solution set of 2x – 3 &gt; 11 – 5x? –3 0 2 4
sergejj [24]
2x - 3 > 11 - 5x      |add 3 to both sides

2x > 14 - 5x      |add 5x to both sides

7x > 14    |divide both sides by 7

x > 2

x = 4
7 0
3 years ago
Read 2 more answers
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