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2 years ago

Please help me with this

Mathematics

1 answer:

GenaCL600 [577]2 years ago

4 0

Answer: slope = 4

Step-by-step explanation:

slope = m = rise/run = y1-y2/x1-x2

9-1/5-3 = 8/2 = 4

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A follow-up study will be conducted with a sample of 20 people from the 300 people who responded yes (support) and no (do not su

mafiozo [28]

Answer:

x = 20 * s / 300

Step-by-step explanation:

In this case, it is solved by means of a rule of three, that is, we know that 20 of 300 answered yes, but in the case of the strata sample, since it is a value that is not mentioned in the problem, we will assume it as " s "and the people who were selected as" x ". would:

20 x

300 s

Therefore, x:

x = 20 * s / 300

and thus they would give us the number of people that would be selected.

For example, if "s" were 240, it would be:

x = 20 * 240/300

x = 16

that is, 16 people would be selected

6 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.