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Tanzania [10]
4 years ago
8

Help pls! Use truth tables to show the following are equivalent:

Mathematics
1 answer:
Darina [25.2K]4 years ago
7 0
B
a
c
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
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Find the value of X<br> Show explanation clearly !!
serious [3.7K]

Answer:

x equals 64

I hope this helps

7 0
3 years ago
Read 2 more answers
If g(x)=x+1/x-2 and h(x)=4-x, what is the value of (g•h)(-3)
beks73 [17]

Answer:

14/5

Step-by-step explanation:

That " • " signifies multiplication.

g(x) = (x + 1) / (x - 2) and h(x) = 4 - x are to be multiplied together to obtain (g·h)(x):  

                (x + 1)(4 - x)

(g·h)(x) = --------------------

                       x - 2

This could be simplified.

But our task is to evaluate this product function at x = -3.  So we replace each instance of x with -3:

                ( -3 + 1 )( 4 - [-3] )           (-2)(7)

(g·h)(-3) = --------------------------  =  ----------- = 14/5

                      -3 - 2                            -5

8 0
3 years ago
I need help for this question plz
ExtremeBDS [4]
Y=180-69=111
4x+7=y
4x+7=111
4x=111-7
4x=104
X=26

Answer: x=26, y=111
4 0
4 years ago
Can you Solve -4x+26=-2
melomori [17]

Answer: x=7

Step-by-step explanation:

-4x+26=-2

-26

-4x=-28

Divide by -4

=7

6 0
3 years ago
Read 2 more answers
Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 280 days a
a_sh-v [17]
First, find the z-score:

z = (value - mean) / sdev
  = (275 - 280) / 15
  = - 0.33

In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)

Looking at the table, we find P(z < 0.33) = 0.6293

Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707

Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
4 0
3 years ago
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