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e-lub [12.9K]
2 years ago
15

Select each type of special quadrilateral that can meet the given condition.

Mathematics
1 answer:
nadya68 [22]2 years ago
8 0

Step-by-step explanation:

To find quadrilateral's you need to find shapes with edges.

<h2>Quadrilateral's:</h2>

Square

Rectangle

Isosceles Trapezoid

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This is my last question i promise
VladimirAG [237]

Answer:

ok

Step-by-step explanation:

x+7+25+2x+4=180

3x+11+25=180

3x=180-36

3x=144

<em>x</em><em>=</em><em>1</em><em>4</em><em>4</em><em>/</em><em>3</em>

<em>x</em><em>=</em><em>4</em><em>8</em>

6 0
2 years ago
PLEASE HELP! You do not have to answer all questions but can someone explain to me on where I am even suppose to begin? I don't
Gre4nikov [31]

Step-by-step explanation:

For problems 1 through 15, evaluate the function at the given x value.

1. f(5) = 2(5) − 1 = 9

2. f(3) = 3² − 3(3) − 1 = -1

3. f(0) = 2(0) + 5 = 5

So on and so forth.

Then, match each answer with the corresponding letter.

The answer to #1 was 9.  9 corresponds to the letter A.

The answer to #2 was -1.  -1 corresponds to the letter C.

The answer to #3 was 5.  5 corresponds to the letter P.

Finally, write each letter with its corresponding problem number.

So everywhere you see a 1, write A.

Everywhere you see a 2, write C.

Everywhere you see a 3, write P.

Continue until every blank has a letter and the problem is solved.

6 0
3 years ago
Rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the
Brut [27]

Answer:

The time that the rocket will hit the ground is 12.87 seconds.

Step-by-step explanation:

Given : The rocket is launched from a tower  y=-16x^2+199x+90. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

To find : The time that the rocket will hit the ground ?

Solution :

When the rocket hit the ground i.e. height became zero y=0,

Equation is y=-16x^2+199x+90

Substitute y=0,

-16x^2+199x+90=0

Using quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(199)\pm\sqrt{(199)^2-4(-16)(90)}}{2(-16)}

x=\frac{-199\pm\sqrt{45361}}{-32}

x=\frac{-199+\sqrt{45361}}{-32},\frac{-199-\sqrt{45361}}{-32}

x=-0.43,12.87

Reject negative value.

The time taken is 12.87 seconds.

5 0
3 years ago
Quickly help :<br> I don’t know WTH I’m doing and my teacher won’t explain
tresset_1 [31]

These are what I call the Two Tired Triangles of Trig, 30/60/90 and 45/45/90. If you learn these cold now you'll save yourself some hassle down the road.  These are generally the only right triangles teachers use when they want 'exact' answers.

Here are the facts to remember:

The ratio of the sides of the 45/45/90 triangle are 1:1:√2

The ratio of the sides of the 30/60/90 triangle are 1:√3:2, with the smallest opposite the 30 degree angle.

OK, let's fill in the angles first.  Where we have a right triangle with 30/60/90 we fill in the missing one. For the half squares, the acute angles are 45 degrees.

For the lengths we apply the ratios.  Hypotenuse of 45 degree right triangle is 4, so sides are 4/√2 = 2√2.  When that's opposite 30 degrees, the other two sides are 2√2×√3 = 2√6 and 2×2√2=4√2.  

2√6 is one side of a square, so all sides.  The diagonal is 2√6×√2=2√12=4√3.  

Half the square side is the smallest leg of a 30/60/90, so √6, with other leg √6×√3=√18=3√2 and hypotenuse 2√6.

6 0
3 years ago
Pleaseeee show your work !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
dexar [7]

Answer:

71

Step-by-step explanation:

6 0
3 years ago
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