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e-lub [12.9K]
3 years ago
15

Select each type of special quadrilateral that can meet the given condition.

Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Step-by-step explanation:

To find quadrilateral's you need to find shapes with edges.

<h2>Quadrilateral's:</h2>

Square

Rectangle

Isosceles Trapezoid

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What's the solution of x+2/5= 12 ?
Feliz [49]

Answer:

11 3/5

Step-by-step explanation:

x+2/5=12

First, you subtract 2/5 from both sides, so the equation becomes:

x=11 3/5

Therefore, x equals 11 3/5

8 0
3 years ago
Read 2 more answers
ESTIMATE THE ANSWER BY ROUNDING EACH NUMBER TO THE NEAREST 10. 961 + 27.8 + 693.0 + 573 +76.4 =
taurus [48]

Answer:

2330

Step-by-step explanation:

In rounding nearest 10,

If the ones place digit is 5 or more then 5 then we round the number to upper 10, while if the ones place digit is less than 5 then we round the number to lower 10,

For example : 34 ≈ 30 while 36 ≈ 40,

Now, given expression,

961 + 27.8 + 693.0 + 573 +76.4

By the above statement 961≈ 960, 27.8 ≈ 30, 693.0 ≈ 690, 573 ≈ 570 and 76.4 ≈ 80,

Hence, 961 + 27.8 + 693.0 + 573 +76.4 = 960 + 30 + 690 + 570 + 80 = 2330.

4 0
3 years ago
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Your turn :will the set of numbers given form a right triangle?<br><br> 8 meter ,10 meter,12 meter
White raven [17]

Yes! It can!

The 12 meters will be the hypotenuse, the 10 meters can be a side and the 8 meters can be another side.

6 0
3 years ago
Find the 8th term of the geometric sequence 3, 12, 48,...
Sophie [7]
\begin{gathered} \text{The first term is 3, the common ratio is 4} \\ \text{That means;} \\ a=3,r=4 \\ \text{The nth term is } \\ T_n=ar^{(n-1)} \\ 8th=3\times4^{(8-1)} \\ 8th=3\times4^7 \\ 8th=3\times16384 \\ 8th=49152 \end{gathered}

4 0
1 year ago
Find the real and/or imaginary solutions by factoring
SIZIF [17.4K]

Answer:


Step-by-step explanation:

1) (x-3),(x-8)

2) 3x^3+3x^2=27x

3 ( x 3^3+ x ^2 − 9 x − 9 )

3 ( x ^2 ( x + 1 ) − 9 ( x + 1 ) )

3 ( ( x + 1)( x ^2 − 9 ) )

3 ( ( x + 1 ) ( x ^2 − 3 ^2 ) )

3 ( x + 1 ) ( x + 3 ) ( x − 3 )

6 0
3 years ago
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