Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
The margin of error is of:
A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So
Rounding up:
A sample of 997 is needed.
Step-by-step explanation:
here is your answer
enjoy
thanks to another users to give this answer
Answer:
Step-by-step explanation:
<em>(17).</em> g(x) = x³ + 4x
f(x) = 4x + 1
( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = <em>4 </em>
<em> + x³ + 16x² + 4x</em>
<em>(19).</em> f(t) = 4t - 4
g(t) = t - 2
( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = <em>19t - 22</em>
<em>(21).</em> h(t) = t + 3
g(t) = 4t + 1
h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = <em>5t - 6</em>
The engine would need three gallons of gas.
12/4=3
