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bixtya [17]
3 years ago
7

Carbon-12 and carbon-13 are isotopes of carbon. Which of the following statements is correct?

Chemistry
1 answer:
kolezko [41]3 years ago
7 0
They both have the same atomic number

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What is the volume of 120 x 1022 molecules of nitric oxide gas, NO, at si B) 2.24L C) 0.0199 L D) 5.02 A) 1120 L
Allisa [31]

Answer: 44.8 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's number}}=\frac{120\times 10^{22}}{6.023\times 10^{23}}=2moles

1 mole of NO occupies volume = 22.4L at STP

Thus 2 moles of magnesium react with=\frac{22.4}{1}\times 2=44.8L

Thus the volume of 120\times 10^{22} molecules of nitric oxide gas is 44.8 L.

5 0
3 years ago
How can you describe the location of vanadium (v, atomic number 23) on the periodic table? Choose all that apply.
Orlov [11]
Vandium is non metal but group 5 period 4 
5 0
3 years ago
When computing using dimensional analysis:
shusha [124]

Answer: unit conversions can be done either simultaneously or separately

Explanation:

6 0
4 years ago
The liquids hexane and water are placed in a test tube. The test tube is stoppered, shaken, and placed in a test tube rack. The
Diano4ka-milaya [45]

The liquids hexane and water are placed in a test tube. The test tube is stoppered, shaken, and placed in a test tube rack. The liquids separate into two distinct layers because hexane and water have different molecular polarities. The answer is number 2.

5 0
3 years ago
Read 2 more answers
A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0
3 years ago
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