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Anna007 [38]
3 years ago
9

Which rate is the lowest price? $3.00/6 lb $2.50/5 lb $2.40/4 lb $2.40/6 lb

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
2.40/6 I believe tell me if it is right
irakobra [83]3 years ago
7 0
$3.00/6=2
$2.50/2=2
$2.40/4=.60
$2.40/6=.40 this is the lowest price
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Help needed!!! Please
Sliva [168]

Answer:

<em>The correct option is:  C. x=6\sqrt{3}, y=12</em>

Step-by-step explanation:

The two angles of the triangle are given as 60° and 60°

As the sum of all three angle in any triangle is always 180°, so the measure of the third angle will be: 180°-(60°+60°) = 180° - 120° = 60°

Now each angle of the triangle is 60°, it means the triangle is equilateral.

The base of the triangle is given as 12. So, the length of each side will be 12.

That means, the value of y=12

Now in the left right triangle.....

Sin(60)=\frac{x}{y} \\ \\ \frac{\sqrt{3}} {2}=\frac{x}{12} \\ \\ 2x=12\sqrt{3} \\ \\ x=6\sqrt{3}

So, the value of x = 6\sqrt{3}

7 0
3 years ago
In the diagram below, the value of y must be
REY [17]

Answer:

y = 45°

Step-by-step explanation:

4 sides = 360°

(2y+1)° + y° + 112° + 112° = 360°

2y + y = 360 - 112 - 112 - 1

3y = 135

y = 135÷3

= 45°

4 0
3 years ago
4a - 7 = 5 <br> What is the answer 2 step equation
Alex777 [14]

Answer:

A= 3

Step-by-step explanation:

4a - 7 = 5

move the constant to the right

4a= 5+7

divide

4a=12

Awnser:

A= 3

3 0
3 years ago
A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%
Mamont248 [21]

Answer:

a. A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\

b. \frac{dA}{dt}= -11.25 \frac{mg}{h}

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0
3 years ago
I don’t really understand this
mars1129 [50]
Uhh me neither thats very complicated
7 0
4 years ago
Read 2 more answers
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