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12345 [234]
2 years ago
5

Determine whether 270.5m . 30.5m is equivalent to each of the following expressions

Mathematics
1 answer:
Leno4ka [110]2 years ago
8 0

Answer:

The answer is 3m^2

Step-by-step explanation:

Work is shown

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Arrange from least to greatest 3,-3, 1, -5, 0, -2, -1, 4, 6.
Darina [25.2K]

Answer:

Step-by-step explanation:

-5,-3,-2,-1,0,1,3,4,6

8 0
3 years ago
What is the area of the parallelogram?
nika2105 [10]

Step-by-step explanation:

The answer is in the picture Hope it helps

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2 years ago
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The opposite sides of a parallelogram are always sometimes or never congruent
KengaRu [80]
Always congruent due to the way the shape is built
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3 years ago
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Which red triangle shows a 90° counterclockwise rotation of the blue triangle? Check all that apply. On a coordinate plane, a bl
Tcecarenko [31]

Question:

1) Blue triangle points; (-1, 4), (-5, 4), and (-1, 1)

Red triangle points; (-4, -1), (-1, -1). and (-4, -5)

2) Blue triangle points (1, 1), (4, 5), (4, 1)

Red triangle points; (-1, 1), (-1, 4). and (-5, 4)

3) Blue triangle points (0, 1), (4, 4), (4, 1)

Red triangle points; (-4, 1), (-4, 4). and (0, 1)

4) Blue triangle points (-5, 4), (-1, 4), (-1, 1)

Red triangle points; (1, 1), (4, 1). and (4, 5)

5) Blue triangle points (-2, 5), (4, 5), (4, 1)

Red triangle points; (-1, 4), (-5, 4). and (-5, -2)

Answer:

The correctly rotated red triangles are those of (1), (2), and (5)

Step-by-step explanation:

In a 90° counterclockwise rotation, every x and y points of the original triangle are switched while the y is turned negative, as shown in the following equation;

(x, y) to (-y, x)

Therefore, the triangles that undergo a 90° counterclockwise rotation are as follows;

1) Blue triangle points; (-1, 4), (-5, 4), and (-1, 1)

Red triangle points; (-4, -1), (-1, -1). and (-4, -5)

(-1, 4) → (-4, -1)

(-5, 4) → (-4, -5)

(-1, 1) → (-1, -1)

Correctly rotated 90° counterclockwise

2) Blue triangle points (1, 1), (4, 5), (4, 1)

Red triangle points; (-1, 1), (-1, 4). and (-5, 4)

(1, 1) → (-1, 1)

(4, 5) → (-5, 4)

(4, 1) → (-1, 4)

Correctly rotated 90° counterclockwise

3) Blue triangle points (0, 1), (4, 4), (4, 1)

Red triangle points; (-4, 1), (-4, 4). and (0, 1)

(0, 1) → (0, 1) ≠ (-1, 0)

(4, 4) → (-4, 4)

(4, 1) → (-4, 1)

Not correctly rotated 90° counterclockwise

4) Blue triangle points (-5, 4), (-1, 4), (-1, 1)

Red triangle points; (1, 1), (4, 1). and (4, 5)

(-5, 4) → (4, 5) ≠ (-4, -5)

(-1, 4) → (4, 1)

(-1, 1) → (1, 1)

Not correctly rotated 90° counterclockwise

5) Blue triangle points (-2, 5), (4, 5), (4, 1)

Red triangle points; (-1, 4), (-5, 4). and (-5, -2)

(-2, 5) → (-5, -2)

(4, 5) → (-5, 4)

(4, 1) → (-1, 4)

Correctly rotated 90° counterclockwise.

8 0
3 years ago
Read 2 more answers
"let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v) = 0.1
morpeh [17]

Here we might have to find p(v intersection w) and for that we use the following formula

p(v U w) = p(v)+p(w)-p(v intersection w)

And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .

Substituting these values in the formula, we will get

0.14 = 0.13 +0.04 -p(v intersection w)

p(v intersection w) =0.13 +0.04 -0.14 = 0.03

So the required answer of the given question is 0.03 .

7 0
2 years ago
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