The grams of Mg(OH)2 produced is calculated as below
calculate the moles of HCl produced =molarity xvolume/1000
= 0.3 x 435/1000= 0.1305 moles
write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O
by use of mole ratio between HCl :MgCl2 which is 2 :1 the moles of HCl = 0.1305 x1/2 =0.0653 moles of MgCl2
mass of MgCl2 = moles x molar mass
= 0.0653mol x95 g/mol = 6.204 grams of MgCl2
If solutions of nh4cl(aq) and nh3(aq) are mixed, the ions in the resulting solution that would be the spectator ions in any acid-base chemistry occurring in the solution would be the chloride ions. The mixture is a common buffer of ammonia and ammonium chloride. NH4Cl is a salt that is soluble in water dissociating into NH4+ and Cl-. The chloride ions are the spectator ions while NH4+ ions would be the conjugate acid for the buffer solution. Buffer solutions are solution which would resist change in pH when acid or a base is being added to the solution. The equilibrium reaction of the buffer solution in this problem would be
NH3 + H2O = OH– + NH4+
Theoretical Yield of H2SO3: 31.2 g
Percent Yield: 67.4%
Theoretical Yield of C2H6: 6.50
Percent Yield: 88.7%
Theoretical Yield of HF: 3.84
Percent Yield: 71.4%
It could be a couple different thing, explain more.<span />
Answer:
The given metal is beryllium.
Explanation:
Given data:
Mass of metal = 74 g
Volume of metal = 40 cm³
Which metal is this = ?
Solution:
First of all we will calculate the density.
it is mass divided by volume.
d = m/v
d = 74 g/40 cm³
d = 1.85 g/cm³
In literature it is given that the density of beryllium is 1.85 g/cm³. Thus given metal is beryllium.
