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Arisa [49]
3 years ago
13

When substances are different from the starting substances, ______ has occurred. a physical change a chemical change no change a

mass change
Chemistry
2 answers:
musickatia [10]3 years ago
5 0
A chemical change... But only if the process is irreversible
Nutka1998 [239]3 years ago
4 0

Answer : The correct option is, Chemical change.

Explanation :

Physical change : It is a change in which there is no new compound or substance is formed. In this, changes occurs only in the phase.  This change is reversible in nature.

For example : Water boiled  : It is a physical change because in this process only phase changes from liquid state to gaseous state.

Chemical change : It is a change in which a new or different compound or substance is formed and releases some amount of energy. There is no changes occurs in the phase. This change is irreversible in nature.

For example : Marshmallows browned  : It is a chemical change due to the burning of sugar. In the sugar burning process, sugar react with oxygen to give carbon dioxide and water as a product.

As per question, when the substances are different from the starting substances, chemical change has occurred.

Hence, the correct option is, Chemical change.

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Which of the following compounds is always part of an aqueous solution?
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A.water.
An aqueous solution is a solution in water.
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Brrunno [24]

Answer:

15.438g H2O

Explanation:

First you need to find the reaction equation:

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Hydrogen is a diatomic molecule so it will have a subscript of 2 on the right hand side. From there we can balance the reaction.    

Then we can use stoichiometry:

34.2g NaOH * (1 mol NaOH/39.908g NaOH) * (2 mol H2O/2 mol NaOH) * (18.015g H2O/1 mol H20) = 15.438g H2O

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3 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

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Amount of NaOCl in this stock solution = 5% of B g

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Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

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B = \frac{0.005}{0.05}

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Explanation:

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