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azamat
3 years ago
7

Based on your knowledge of oxygen ion and that Iron can exist as a +2 or a +3 ion. In the formula FeO, what is the charge of the

Fe ion?
+2

+3

Chemistry
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

+2

Explanation:

Oxygen ions always have the charge of -2. Since Fe is in the transition metal stage, it doesn't have a specific set of ions unless specifically shown. In the equation FeO, we would have to have a +2 charge when equalling the two atoms together. So when combines the charges would look like:

Fe_{+2} + O_{-2} = FeO

I am happy to help with any other questions you might have, and I will continue to work to providing the best answers for you :)

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Explain how you would find the mass percent<br> of each element in water.
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Answer:

finding the mass percentage oven element in a compound might sound complicated, but the calculation is simple. For example, to determine the mass percentage of hydrogen in water H2O, divide the major mass of hydrogen by the total molar mass of water and then multiply the result by 100

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3 years ago
Johanna makes the table below to organize her notes about centripetal forces. Which type of force should she place in the cell m
Valentin [98]

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

Centripetal force is defined as the force that acts on a body moving in a circular path and is directed towards the center around which the body is moving.

Mathematically,

F_c=\frac{mv^2}{r}

Where,

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From the above relation, X corresponds to the radius and Y corresponds to the tangential velocity.

Hence, the correct answer is option C.

3 0
3 years ago
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What is the volume of 40.0 grams of argon gas at STP ?
MrRa [10]

Answer:

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General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Aqueous Solutions</u>

  • States of Matter

<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

[Given] 40.0 g Ar

[Solve] L Ar

<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 40.0 \ g \ Ar(\frac{1 \ mol \ Ar}{39.95 \ g \ Ar})(\frac{22.4 \ L \ Ar}{1 \ mol \ Ar})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 24.9235 \ L \ Ar

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

24.9235 L Ar ≈ 24.9 L Ar

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