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azamat
4 years ago
7

Based on your knowledge of oxygen ion and that Iron can exist as a +2 or a +3 ion. In the formula FeO, what is the charge of the

Fe ion?
+2

+3

Chemistry
1 answer:
DerKrebs [107]4 years ago
6 0

Answer:

+2

Explanation:

Oxygen ions always have the charge of -2. Since Fe is in the transition metal stage, it doesn't have a specific set of ions unless specifically shown. In the equation FeO, we would have to have a +2 charge when equalling the two atoms together. So when combines the charges would look like:

Fe_{+2} + O_{-2} = FeO

I am happy to help with any other questions you might have, and I will continue to work to providing the best answers for you :)

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1) Choose the correct statement from the options below.
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<u>Answer:</u>

For 1: The correct answer is option D.

For 2: The correct answer is option A.

<u>Explanation:</u>

There are two types of molecules which can be categorized on the basis of electronegativity difference:

  • <u>For 1:</u>

Polar molecules: In these type of molecules, the two atoms combining must be different so that a dipole can be created and for that the electronegativity of two atoms combining must not be same. The negative dipole of charge is created on the electronegative atom and positive dipole or charge is created on the electropositive atom.

Hence, the correct answer is option D.

  • <u>For 2:</u>

Non-polar molecules are defined as the molecules which do not have any dipole and is formed when two atoms of same element combine together which have the same electronegativity. The electronegativity difference of these molecules is 0.

Hence, the correct answer is A.

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3 years ago
All of the following are reasons why equations or balanced EXCEPT
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Answer:

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Explanation:

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3 years ago
Name this compound <br><br> please helppp thank you!!!
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Answer:

Sodium sulfide is the chemical compound with the formula Na 2 S, or more commonly its hydrate Na 2 S·9H 2 O. Both are colorless water-soluble salts that give strongly alkaline solutions. When exposed to moist air, Na 2 S and its hydrates emit hydrogen sulfide , which smells like rotten eggs.

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A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant
KiRa [710]

Answer:

V_2=2.995L\\\\W=248.5J

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

P_1V_1=P_2V_2

So we solve for V_2 by firstly computing the initial pressure:

P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L}  =11.98atm

V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L

Finally, we can compute the work by using the following formula:

W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J

Best regards.

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Dot and cross diagram for ionic compounds
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