Find 2 numbers if their sum is 3/5 and their difference is 7 and 1/5
1 answer:
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Answer:
P(x) = (x - 1)(x + 2)(x - 3)(3x + 1)
Step-by-step explanation:
Since P(1) = 0 and P(- 2) = 0, then
(x - 1) and (x + 2) are factors of P(x)
(x - 1)(x + 2) = x² + x - 2 ← is also a factor of P(x)
dividing 3 - 5x³ - 17x² + 13x + 6 by x² + x - 2 gives
P(x) = (x - 1)(x + 2)(3x² - 8x - 3) = (x - 1)(x + 2)(x - 3)(3x + 1)
<u>Answer:</u>
A. y = -2 - cos(x-π)
<u>Explanation:</u>
<u>The general form of the trig equation is:</u>
y = A sin (Bx + C) + D
where:
A is the amplitude
is the period
is the phase shift
D is the vertical shift
<u>Now, let's check the choices:</u>
<u>A. y = -2 - cos(x-π)</u>
Therefore, the function has a phase shift of π
<u>B. y = 3 cos(4x)</u>
Therefore, the function has no phase shift
<u>C. y = tan(2x)</u>
Therefore, the function has no phase shift
<u>D. y = 1 + sin(x)</u>
Therefore, the function has no phase shift
<u>Based on the above,</u> the correct answer is A
Hope this helps :)