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MariettaO [177]
3 years ago
12

A cylinder shaped juice pitcher has a diameter of 12 cm and a height of 25 cm. What volume of juice does the pitcher contain whe

n it is 25% full? Use 3.14 to approximate pi. Enter your answer as a decimal to the tenths place in the box
Mathematics
2 answers:
malfutka [58]3 years ago
7 0
Radius of pitcher = 12/2 = 6cm
Volume of pitcher = pi x r^2 x h = 3.14 x 6^2 x 25 = 2,826 cm^3
Volume when pitcher is 25% full = 0.25 x 2,826 = 706.5 cm^3
kap26 [50]3 years ago
7 0

Your answer is 706.5, I took the test.

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The dot plots below show the number of points scored by Sam and Daniel in 15 basketball games.
Bas_tet [7]

Answer:

B.

Step-by-step explanation:

Sam median = 12 which has 3 points scored.

Daniel median = 16 which has 3 points scored.

Both scored the same amount of data which is 3 points.

Both the ranges are 16. so it cant be A or C.

3 0
2 years ago
Which equation dose not represent a linear function of X
Naya [18.7K]

Answer:

D

Step-by-step explanation:

whenever you see this ^ you now it's not linear equation

8 0
3 years ago
Help me solve this equation and show work <br><br> 11d + 17b = 95 <br> d + b = 7
sweet-ann [11.9K]

Answer:

{d,b}={4,3}

Step-by-step explanation:

[1]    11d + 17b = 95

  [2]    d + b = 7

Graphic Representation of the Equations :

   17b + 11d = 95        b + d = 7  

 

Solve by Substitution :

// Solve equation [2] for the variable  b

 [2]    b = -d + 7

// Plug this in for variable  b  in equation [1]

  [1]    11d + 17•(-d +7) = 95

  [1]    -6d = -24

// Solve equation [1] for the variable  d

  [1]    6d = 24

  [1]    d = 4

// By now we know this much :

   d = 4

   b = -d+7

// Use the  d  value to solve for  b

   b = -(4)+7 = 3

Solution :

{d,b} = {4,3}

4 0
2 years ago
Read 2 more answers
(5x² – 8x + 1) + (2x² - 4x – 11)
djverab [1.8K]

Answer:

7x²-12x-10

Step-by-step explanation:

(5x²-8x+1) + (2x²-4x-11)

combine like terms

7x²-12x-10

7 0
3 years ago
Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win
Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Similarly,

P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6}  = \dfrac{1}{36}

7 0
3 years ago
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