Answer:
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Step-by-step explanation:
Here we have that for dependent events,
From the options, we have;
= 0.533
P(drug) = 0.6
P(drug and fatigue) = 0.32
Therefore
P(drug and fatigue) = P(drug)×
= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.
Hello! :)
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Answer:
407
Step-by-step explanation:
The answer is 407 because....
300/184 x 250
=407.60
So the answer is 407.60 which rounds to 407
ANSWER: X=407
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Hope this helps! :)
By: BrainlyMember ^-^
Good luck!
Answer:
p=5
Step-by-step explanation:
3+p=8
subtract 3 from each side
p=5
Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.
So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:
<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>
where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.
