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Verizon [17]
3 years ago
13

A car moving at a constant speed passed a timing device at t= 0. After 8 seconds, the car has

Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

d = 94t

Step-by-step explanation:

The rate of speed is 752 ft / 8 sec = 94 ft/sec

d = 94t

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Answer:

10i

Step-by-step explanation:

√(-100)

Use the imaginary number rule  i=\sqrt{-1}

√(-1) × √(100)

i × √(10²)

i × 10

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25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

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x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
2 years ago
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