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pentagon [3]
3 years ago
9

Chemistry: An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container, if the gas has a press

ure of the 845mmHg at 22degrees Celsius? ​
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

There are 29.4 grams of oxygen in the container

Explanation:

<u>Step 1: </u>Data given

Volume = 20.0 L

Pressure = 845 mmHg

Temperature = 22.0 °C

Molar mass of O2 = 32 g/mol

<u>Step 2:</u> Ideal gas law

p*V = n*R*T

⇒ p = the pressure of the gas = 845 mmHg = 1.11184

⇒ V = the volume of the gas = 20.0 L

⇒ n = the number of moles = TO BE DETERMINED

⇒R = the gasconstant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C + 273 = 295 Kelvin

n = (p*V)/(R*T)

n = (1.11184*20.0)/(0.08206*295)

n = 0.9186 moles

<u>Step 3:</u> Calculate mass of NO2

Mass of O2 = Moles O2 * Molar mass O2

Mass of O2 = 0.9186 moles * 32 g/mol

Mass of O2 = 29.4 grams

There are 29.4 grams of oxygen in the container

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Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

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make n the subject of the equation

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The reaction is not balanced

<h3>Further explanation</h3>

Given

Reaction

2Fe(s)+3O₂(g)⇒2Fe₂O₃(s)

Required

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